如何将列表拆分为大小相等的块？

如何将任意长度的列表拆分为大小相等的块？

_{See also: How to iterate over a list in chunks https://stackoverflow.com/q/434287.
To chunk strings, see Split string every nth character? https://stackoverflow.com/questions/9475241.}

这是一个生成均匀大小块的生成器：

def chunks(lst, n):
    """Yield successive n-sized chunks from lst."""
    for i in range(0, len(lst), n):
        yield lst[i:i + n]

import pprint
pprint.pprint(list(chunks(range(10, 75), 10)))
[[10, 11, 12, 13, 14, 15, 16, 17, 18, 19],
 [20, 21, 22, 23, 24, 25, 26, 27, 28, 29],
 [30, 31, 32, 33, 34, 35, 36, 37, 38, 39],
 [40, 41, 42, 43, 44, 45, 46, 47, 48, 49],
 [50, 51, 52, 53, 54, 55, 56, 57, 58, 59],
 [60, 61, 62, 63, 64, 65, 66, 67, 68, 69],
 [70, 71, 72, 73, 74]]

对于 Python 2，使用xrange代替range:

def chunks(lst, n):
    """Yield successive n-sized chunks from lst."""
    for i in xrange(0, len(lst), n):
        yield lst[i:i + n]

下面是一个列表理解单行代码。不过，上面的方法更可取，因为使用命名函数使代码更容易理解。对于Python 3：

[lst[i:i + n] for i in range(0, len(lst), n)]

对于Python 2：

[lst[i:i + n] for i in xrange(0, len(lst), n)]