我正在为 cmd 编写包装器，但在重定向标准输入时遇到问题

好的，这就是我正在做的 - 我想编写一个 .net 应用程序，将标准输出/输入重定向到 Richtextbox。我已经让它工作得很好，但是一旦我将标准输入添加到混合中，我的读取命令就会冻结。这是我的表单中的相关代码。

        Shell = new Process();
        Shell.StartInfo.FileName = "cmd";

        Shell.StartInfo.UseShellExecute = false;
        Shell.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
        Shell.StartInfo.CreateNoWindow = true;

        //Shell.StartInfo.RedirectStandardInput = true;
        Shell.StartInfo.RedirectStandardOutput = true;
        Shell.StartInfo.RedirectStandardError = true;

        Shell.EnableRaisingEvents = true;
        Shell.OutputDataReceived += new DataReceivedEventHandler(Shell_OutputDataReceived);
        Shell.ErrorDataReceived += new DataReceivedEventHandler(Shell_OutputDataReceived);

        Shell.Start();

        Timer consoleReader = new Timer();
        consoleReader.Interval = 200;
        consoleReader.Tick += new EventHandler(consoleReader_Tick);
        consoleReader.Start();
    }

    void consoleReader_Tick(object sender, EventArgs e)
    {
        textArea.AppendText(Shell.StandardOutput.ReadToEnd());
    }

我也尝试过使用 Process 类中可用的异步读取方法来执行此操作，但是，一旦我将 standardinputredirect = true 添加到组合中，它就会在读取一行左右后挂起。

大家有什么想法吗？

[[编辑]] 好的，这是一个示例程序。我将此代码移至控制台应用程序中以稍微简化一些事情。为什么这个坏了？

using System;
using System.Collections.Generic;
using System.Text;
using System.Diagnostics;

namespace TestAsConsoleApp
{
    class Program
    {
        static Process Shell;
        static void Main(string[] args)
        {
            Shell = new Process();
            Shell.StartInfo.FileName = "cmd";

            Shell.StartInfo.UseShellExecute = false;
            Shell.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
            Shell.StartInfo.CreateNoWindow = true;

            Shell.StartInfo.RedirectStandardInput = true;
            Shell.StartInfo.RedirectStandardOutput = true;
            Shell.StartInfo.RedirectStandardError = true;

            Shell.Start();

            Shell.EnableRaisingEvents = true;
            Shell.OutputDataReceived += new DataReceivedEventHandler(Shell_OutputDataReceived);
            Shell.BeginOutputReadLine();

            Shell.WaitForExit();
        }

        static void Shell_OutputDataReceived(object sender, DataReceivedEventArgs e)
        {
            if (e.Data != null)
                Console.WriteLine(e.Data);
        }
    }
}

修改后的程序看起来并没有被破坏。您创建一个进程请求重定向所有流。您触发创建的流程输出的异步读取。然后你就等着吧。在您的情况下，创建的 cmd.exe 不会在其输入流中获取任何内容，因此它不会产生任何输出。可以尝试下面的程序。运行它并给出一些命令，例如 dir 等，它将产生输出。希望我没有误解你的问题。

    using System;
    using System.Collections.Generic;
    using System.Text;
    using System.Diagnostics;

    namespace TestAsConsoleApp
    {
        class Program
        {
            static Process Shell;
            static void Main(string[] args)
            {
                Shell = new Process();
                Shell.StartInfo.FileName = "cmd";

                Shell.StartInfo.UseShellExecute = false;
                Shell.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
                Shell.StartInfo.CreateNoWindow = true;

                Shell.StartInfo.RedirectStandardInput = true;
                Shell.StartInfo.RedirectStandardOutput = true;
                Shell.StartInfo.RedirectStandardError = true;

                Shell.Start();
                //Shell.StandardInput.WriteLine("dir");

                Shell.EnableRaisingEvents = true;
                Shell.OutputDataReceived += new DataReceivedEventHandler(Shell_OutputDataReceived);
                Shell.BeginOutputReadLine();
//read input from your programs input and forward that to the created cmd 's input
                do
                {
                    string aLine = Console.ReadLine();
                    Shell.StandardInput.WriteLine(aLine);
                    if (aLine.ToLower() == "exit")
                        break;
                }while(true);

                Shell.WaitForExit();
            }

            static void Shell_OutputDataReceived(object sender, DataReceivedEventArgs e)
            {
                if (e.Data != null)
                    Console.WriteLine(e.Data);
            }
        }
    }