获取每个人每天的最短日期时间的记录

CREATE TABLE IF NOT EXISTS `accesscards` (
    `id` int(11) NOT NULL AUTO_INCREMENT,
    `department` varchar(255) NOT NULL,
    `name` varchar(255) NOT NULL,
    `entrydates` datetime NOT NULL, PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;

INSERT INTO `accesscards` (`id`, `department`, `name`, `entrydates`) VALUES
(1, 'test', 't1', '2013-12-06 16:10:00'),
(2, 'test', 't1', '2013-12-06 15:10:00'),
(3, 'test', 't1', '2013-12-07 15:11:00'),
(4, 'test', 't1', '2013-12-07 15:24:00'),
(5, 'test', 't2', '2013-12-06 16:10:00'),
(6, 'test', 't2', '2013-12-06 16:25:00'),
(7, 'test', 't2', '2013-12-07 15:59:00'),
(8, 'test', 't2', '2013-12-07 16:59:00');

上面是我的查询，我想获取一个人每天的记录。该记录应该有当天的最小日期时间。我需要该日期时间的完整记录

我的预期输出here http://www.sqlfiddle.com/#!2/66c3f/2

我尝试使用

SELECT id, MIN(entrydates) FROM accesscards WHERE 1=1 AND name!='' GROUP BY DATE(entrydates) ORDER BY id

但对于“t1”，我得到 id=1 和第一行的输入日期。

请帮帮我。如果重复则提供链接。

SELECT a1.*
FROM accesscards a1
JOIN (SELECT name, MIN(entrydates) mindate
      FROM accesscards
      WHERE name != ''
      GROUP BY name, date(entrydates)) a2
ON a1.name = a2.name AND a1.entrydates = a2.mindate

DEMO http://www.sqlfiddle.com/#!2/66c3f/3