1.C++给字符数组内文件名排序
假设我们获得到的文件名列表是一个二维字符数组,给这样的数据排序首先要获得排序所需的关键字,如下:
void getNum(char dstChar[], int* num)
{
//首先要知道字符串长啥样,用字符串中的哪几个位置的数做排序依据
string strname = dstChar; // "./yitu_300/0025.jpeg"
string numname = strname.substr(11, 4); //取字符串的11位开始,取4个字符
*num = stoi(numname); //*num=25
}
void Bobsort(char (*image_filename_list)[256], int image_number)
{
for (int i = 0; i < image_number; i++)
{
for (int j = 0; j < image_number - i-1; j++)
{
int numj, numj1;
getNum(image_filename_list[j], &numj);
getNum(image_filename_list[j+1], &numj1);//这里排序就是按照刚刚取出的数据做判断依据
if (numj > numj1)
{
char tmp[256] = { 0 };
strcpy(tmp, image_filename_list[j + 1]);
strcpy(image_filename_list[j + 1], image_filename_list[j]);
strcpy(image_filename_list[j], tmp);
}
}
}
}
void SortCharAry()
{
char filename[][256] = { "./ddddd_300/0025.jpeg", "./dddd_300/0064.jpeg", "./dddd_300/0002.jpeg" };
Bobsort(filename, 3);
for (int i = 0; i < 3; i++)
{
printf("%s\n", filename[i]);
}
}