Given a non-empty array of integers, every element appears twice except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
Example 1:
Input: [2,2,1]
Output: 1
Example 2:
Input: [4,1,2,1,2]
Output: 4
Solution:
class Solution {
public int singleNumber(int[] nums) {
int len = nums.length;
int xor = nums[0];
for(int i = 1; i < len; i++) {
xor ^= nums[i];
}
return xor;
}
}
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