[C语言]计算某字符出现次数

题目

代码

#include <stdio.h>

int main(){
    char str[1000];
    char ch;
    char* s;
    int count = 0;
    
    scanf("%[^\n] %c",str,&ch);//!!! %[^]的用法
    s = str;
    while(*s != '\0'){
        if(ch>=97){
            if(*s == ch || *s == (ch-32))
                count++;
            s++;    
        }
        else if(ch<=57){
            if(*s == ch)
                count++;
            s++;            
        }
        else{
            if(*s == ch || *s == (ch+32))
                count++;
            s++;
        }
    }
    printf("%d",count);
    
    return 0;
}