如何在Python抽象类中创建抽象属性？

在下面的代码中，我创建了一个基本抽象类Base。我想要继承自的所有类Base提供name财产，所以我把这个财产@abstractmethod.

然后我创建了一个子类Base，称为Base_1，它旨在提供一些功能，但仍然保持抽象。没有name财产在Base_1，但是 python 会毫无错误地实例化该类的对象。如何创建抽象属性？

from abc import ABCMeta, abstractmethod

class Base(object):
# class Base(metaclass = ABCMeta): <- Python 3
    __metaclass__ = ABCMeta
    def __init__(self, str_dir_config):
        self.str_dir_config = str_dir_config
    
    @abstractmethod
    def _do_stuff(self, signals):
        pass
    
    @property    
    @abstractmethod
    def name(self):
        """This property will be supplied by the inheriting classes
        individually.
        """
        pass
    

class Base1(Base):
    __metaclass__ = ABCMeta
    """This class does not provide the name property and should
    raise an error.
    """
    def __init__(self, str_dir_config):
        super(Base1, self).__init__(str_dir_config)
        # super().__init__(str_dir_config) <- Python 3
    
    def _do_stuff(self, signals):
        print "Base_1 does stuff"
        # print("Base_1 does stuff") <- Python 3

class C(Base1):
    @property
    def name(self):
        return "class C"
    

if __name__ == "__main__":
    b1 = Base1("abc")

Since Python 3.3修复了一个错误，这意味着property()当应用于抽象方法时，装饰器现在可以正确识别为抽象。

注意：顺序很重要，您必须使用@property above @abstractmethod

Python 3.3+： (蟒蛇文档):

from abc import ABC, abstractmethod

class C(ABC):
    @property
    @abstractmethod
    def my_abstract_property(self):
        ...

Python 2： (蟒蛇文档)

from abc import ABCMeta, abstractproperty

class C:
    __metaclass__ = ABCMeta

    @abstractproperty
    def my_abstract_property(self):
        ...