因此,我通过将核心转储传输到 Python 脚本来解决这个问题,然后根据线程名称正则表达式模式到可执行文件名称的硬编码映射来重命名核心文件名。
以下是将核心通过管道传输到脚本的方法:
/sbin/sysctl -q -w "kernel.core_pattern=|/opt/mydirectory/bin/core_helper.py --corefile /opt/mydirectory/coredumps/%e.%p.core"
/sbin/sysctl -q -w "kernel.core_pipe_limit=8"
这是 core_helper.py 中的一个类的片段。作为奖励,如果您为核心文件名提供 .gz 扩展名,它将使用 gzip 压缩核心转储。
class CoredumpHelperConfig:
def __init__(self, corefile):
self.corefile = corefile
# Work-around: Linux is putting the thread name into the
# core filename instead of the executable. Revert the thread name to
# executable name by using this mapping.
# The order is important -- the first match will be used.
threadNameToExecutableMapping = [# pattern , replace
(r'fooThread.*', r'foo'),
(r'barThread.*', r'foo'),
]
def processCore(self):
(dirname, basename) = os.path.split(self.corefile)
# E.g. fooThread0.21495.core (no compression) or fooThread0.21495.core.gz (compression requested)
match = re.match(r'^(\w+)\.(\d+)\.(core(\.gz)?)$', basename)
assert match
(threadName, pid, ext, compression) = match.groups()
# Work-around for thread name problem
execName = threadName
for (pattern, replace) in CoredumpHelperConfig.threadNameToExecutableMapping:
match = re.match(pattern, threadName)
if match:
execName = re.sub(pattern, replace, threadName)
break
self.corefile = os.path.join(dirname, '.'.join([execName, pid, ext]))
# Pipe the contents of the core into corefile, optionally compressing it
core = open(self.corefile, 'w')
coreProcessApp = "tee"
if(compression):
coreProcessApp = "gzip"
p = subprocess.Popen(coreProcessApp, shell=True, stdin=sys.stdin, stdout=core, stderr=core)
core.close()
return True
我将把它作为练习留给读者如何编写文件的其余部分。