我想向 WCF 休息服务发送一个发布请求，如您所见：

Guid id;
id = Guid.NewGuid();

var httpWebRequest = (HttpWebRequest)WebRequest.Create("http://localhost:47026/NewsRepository.svc/AddNews");
httpWebRequest.ContentType = "application/json";
httpWebRequest.Method = "POST";
using (var streamWriter = new StreamWriter(httpWebRequest.GetRequestStream()))
{
    string json = new JavaScriptSerializer().Serialize(new
    {       
        id = id,
        Subject="wfwf",
        ViewerCounter="1",
        Content="fsdsd",
        SubmitDatatime="2012/12/12",
        ModifiedDateTime="2012/12/12",
        PublisherName="sdaadasd",
        PictureAddress="adfafsd",
        TypeOfNews="adsadaad"                       
    });

    streamWriter.Write(json);
}
try 
{ 
    var httpResponse = (HttpWebResponse)httpWebRequest.GetResponse();
    using (var streamReader = new StreamReader(httpResponse.GetResponseStream()))
    {
        var result = streamReader.ReadToEnd();
    }
}
catch(Exception er)
{
    MessageBox.Show(er.ToString());
}

但我收到错误 - 400 bad request。所以我跟踪我的 WCF 日志文件，发现了这个错误：

反序列化 CMSManagement.Domain.Entity.News 类型的对象时出错。日期时间内容“2012/12/12”不按照 JSON 的要求以“/Date(”开头并以“)/”结尾。

在我亲爱的朋友@svek 代码之后。结果是这样的：

Guid id;
id = Guid.NewGuid();

var httpWebRequest = (HttpWebRequest)WebRequest.Create("http://localhost:47026/NewsRepository.svc/AddNews");
httpWebRequest.ContentType = "application/json";
httpWebRequest.Method = "PUT";
using (var streamWriter = new StreamWriter(httpWebRequest.GetRequestStream()))
{
    JsonSerializerSettings microsoftDateFormatSettings = new JsonSerializerSettings
    {
        DateFormatHandling = DateFormatHandling.MicrosoftDateFormat
    };

    string json = JsonConvert.SerializeObject(new
    {
        id = id,
        Subject = "wfwf",
        ViewerCounter = "1",
        Content = "fsdsd",
        SubmitDatatime = "2012/12/12",
        ModifiedDateTime = "2012/12/12",
        PublisherName = "sdaadasd",
        PictureAddress = "adfafsd",
        TypeOfNews = "adsadaad"
    }, microsoftDateFormatSettings);
    streamWriter.Write(json);
}
try 
{ 
    var httpResponse = (HttpWebResponse)httpWebRequest.GetResponse();
    using (var streamReader = new StreamReader(httpResponse.GetResponseStream()))
    {
        var result = streamReader.ReadToEnd();
    }
}
catch(Exception er)
{
    MessageBox.Show(er.ToString());
}

但我得到同样的错误。为什么？

使用 JsonConvert

而不是使用

string json = new JavaScriptSerializer().Serialize( new {...} );

use

//using Newtonsoft.Json;
string json = JsonConvert.SerializeObject(new {...} );

设置日期时间格式

在 Json.NET 4.5 之前，日期是使用 Microsoft 格式编写的：“/Date(1198908717056)/”。如果您想使用此格式，或者您想保持与 Microsoft JSON 序列化程序或旧版本的 Json.NET 的兼容性，请更改日期格式处理设置为 MicrosoftDateFormat。

Source: http://www.newtonsoft.com/json/help/html/DatesInJSON.htm

默认 Json.NET 4.5 格式

// default as of Json.NET 4.5
string isoJson = JsonConvert.SerializeObject(data);
// { "MyDateProperty":"2009-02-15T00:00:00Z" }

微软日期格式

JsonSerializerSettings microsoftDateFormatSettings = new JsonSerializerSettings
{
    DateFormatHandling = DateFormatHandling.MicrosoftDateFormat
};

string microsoftJson = JsonConvert.SerializeObject(data, microsoftDateFormatSettings);
// { "MyDateProperty":"\/Date(1234656000000)\/" }

JavaScript JSON 格式

string javascriptJson = JsonConvert.SerializeObject(data, 
    new JavaScriptDateTimeConverter());
// { "MyDateProperty":new Date(1234656000000)}

解决方案代码

这是您问题的完整工作解决方案：

JsonSerializerSettings microsoftDateFormatSettings = new JsonSerializerSettings
{
    DateFormatHandling = DateFormatHandling.MicrosoftDateFormat
};

string json = JsonConvert.SerializeObject(new
{
    id = id,
    Subject = "wfwf",
    ViewerCounter = "1",
    Content = "fsdsd",
    SubmitDatatime = "2012/12/12",
    ModifiedDateTime = "2012/12/12",
    PublisherName = "sdaadasd",
    PictureAddress = "adfafsd",
    TypeOfNews = "adsadaad"

}, microsoftDateFormatSettings); // ⇦ Added the format argument here

using (StreamWriter streamWriter = new StreamWriter(httpWebRequest.GetRequestStream()))
{
    JsonSerializer serializer = new JsonSerializer();
    serializer.Serialize(streamWriter, json);
}