I'm trying to sort snapshot by timestamp but returns original order.
data structure looks like this
我有两个快照,时间戳是-1536025466539
and -1536025893015
.
所以,我期望-1536025893015
排序后排在第一位。
有谁知道如何正确排序?
Code:
Map<dynamic, dynamic> map = snapshot.data?.snapshot?.value;
map.values.toList().sort((a, b) {
return a['timestamp'].compareTo(b['timestamp']);
// also not work return b['timestamp'].compareTo(a['timestamp']);
});
从上面的代码来看,您似乎没有variable
保存清单。
Map<dynamic, dynamic> map = {
"one": {"timestamp": 1},
"two": {"timestamp": 2}
};
List list = map.values.toList(); //variable which holds new list created from Map.
//As it new list, any change in list will not have no impact on map.
list.sort((a, b) {
return b["timestamp"].compareTo(a["timestamp"]);
}); // inplace sort
print(list); // [{timestamp: 2}, {timestamp: 1}]
如果你想key
也在结果中,
var list = map.entries.toList();
list.sort((a, b) => b.value["timestamp"].compareTo(a.value["timestamp"]));
var list2 = list.map((a) => {a.key: a.value}).toList();
print(list2); // [{two: {timestamp: 2}}, {one: {timestamp: 1}}]
本文内容由网友自发贡献,版权归原作者所有,本站不承担相应法律责任。如您发现有涉嫌抄袭侵权的内容,请联系:hwhale#tublm.com(使用前将#替换为@)