尽管传递了参数列表，为什么将变量传递给 subprocess.Popen 不起作用？

我有一个脚本调用另一个Python脚本subprocess.Popen。但是因为我有参数存储在变量中

servers[server]['address']
servers[server]['port']
servers[server]['pass']

我无法执行该命令

p = subprocess.Popen(
    ["python mytool.py -a ", servers[server]['address'], "-x", servers[server]['port'], "-p", servers[server]['pass'], "some additional command"],
    shell=True,
    stdout=subprocess.PIPE
)

Drop shell=True. 论据Popen()在 Unix 上的处理方式不同，如果shell=True:

import sys
from subprocess import Popen, PIPE

# populate list of arguments
args = ["mytool.py"]
for opt, optname in zip("-a -x -p".split(), "address port pass".split()):
    args.extend([opt, str(servers[server][optname])])
args.extend("some additional command".split())

# run script
p = Popen([sys.executable or 'python'] + args, stdout=PIPE)
# use p.stdout here...
p.stdout.close()
p.wait()

请注意，通过shell=True对于具有外部输入的命令存在安全隐患，如警告所述在文档中.