用数组中缺失周期的行填充二维数组

我有一个包含 1 - 13 期间的数组。有时，该数组并不包含所有期间的数据，我需要填写缺失的数据，例如：

$array = [
    ['period' =>  7, 'y' => 20],
    ['period' =>  8, 'y' => 20.50],
    ['period' =>  9, 'y' => 7020],
    ['period' => 10, 'y' => 6520],
    ['period' => 11, 'y' => 65920],
    ['period' => 12, 'y' => 62820],
    ['period' => 13, 'y' => 6120],
];

对于这种情况，我需要运行一个 php 循环来填充缺少的前 6 个周期0 y价值观。我尝试过各种循环，但没有任何乐趣。

期望的输出：

[
    ['period' =>  1, 'y' => 0],
    ['period' =>  2, 'y' => 0],
    ['period' =>  3, 'y' => 0],
    ['period' =>  4, 'y' => 0],
    ['period' =>  5, 'y' => 0],
    ['period' =>  6, 'y' => 0],
    ['period' =>  7, 'y' => 20],
    ['period' =>  8, 'y' => 20.50],
    ['period' =>  9, 'y' => 7020],
    ['period' => 10, 'y' => 6520],
    ['period' => 11, 'y' => 65920],
    ['period' => 12, 'y' => 62820],
    ['period' => 13, 'y' => 6120],
]

您可以使用标准数组方法获得良好的语义。例如：

<?php
$in = [
    ['period' =>  7, 'y' => 20],
    ['period' =>  8, 'y' => 20.50],
    ['period' =>  9, 'y' => 7020],
    ['period' => 10, 'y' => 6520],
    ['period' => 11, 'y' => 65920],
    ['period' => 12, 'y' => 62820],
    ['period' => 13, 'y' => 6120],
];

// collect available periods
$available = array_column($in, 'period');

// calculate missing periods
$missing = array_diff(range(1, 13), $available);

// transform missing to correct format
$addition = array_map(function ($period) { return ['period' => $period, 'y' => 0]; }, $missing);

// add missing to input
$out = array_merge($in, $addition);

// sort by period
usort($out, function ($a, $b) {
    return $a['period'] <=> $b['period'];
});

// done
print_r($out);

demo: https://3v4l.org/2fDYW