我遇到过这种情况：
单击 html 提交按钮，我调用views.stream_response哪个“激活”views.stream_response_generator哪个“激活”流.py并返回一个流式Http响应我每秒都会看到一个渐进的数字，直到m at /stream_response/:
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8 //e.g. my default max value for m
流.py
from django.template import Context, Template
import time
def streamx(m):
lista = []
x=0
while len(lista) < m:
x = x + 1
time.sleep(1)
lista.append(x)
yield "<div>%s</div>\n" % x #prints on browser
print(lista) #print on eclipse
return (x)
views.py
def stream_response(request): // unified the three functions as suggested
if request.method == 'POST':
form = InputNumeroForm(request.POST)
if form.is_valid():
m = request.POST.get('numb', 8)
resp = StreamingHttpResponse(stream.streamx(m))
return resp
forms.py
from django.db import models
from django import forms
from django.forms import ModelForm
class InputNumero(models.Model):
m = models.IntegerField()
class InputNumeroForm(forms.Form):
class Meta:
models = InputNumero
fields = ('m',)
urls.py
...
url(r'^homepage/provadata/$', views.provadata),
url(r'^stream_response/$', views.stream_response, name='stream_response'),
...
主页/provadata.html
<form id="streamform" action="{% url 'stream_response' %}" method="POST">
{% csrf_token %}
{{form}}
<input id="numb" type="number" />
<input type="submit" value="to view" id="streambutton" />
</form>
如果我删除“8”并仅使用m = request.POST.get('numb')我得到：
/stream_response/ 处的 ValueError 视图 homepage.views.stream_response 未返回 HttpResponse 对象。 它返回 None 相反。
因此，如果我尝试提交，它只需要默认值 8（并且有效），但不会接受我的表单输入。有什么问题吗？
views.py
def stream_response(request):
form = InputNumeroForm()
if request.method == 'POST':
form = InputNumeroForm(data=request.POST)
if form.is_valid():
#Accessing the data in cleaned_data
m = form.cleaned_data['numero']
print("My form html: %s" % form)
print ("My Number: %s" % m) #watch your command line
print("m = ", m)
resp = StreamingHttpResponse(stream.streamx(m))
return resp
#If not post provide the form here in the template :
return render(request, 'homepage/provadata.html', {'form': form,})
forms.py
class InputNumeroForm(forms.Form):
numero = models.IntegerField()
主页/provadata.py
<form action="/stream_response/" method="POST">
{% csrf_token %}
{{form}} <!--issue: does not appear on the html !!!!!-->
<input type="number" name="numero" /> <!--so I write this-->
<input type="submit" value="to view" />
</form>
如果我给出输入，例如7 从键盘：
/stream_response/处的KeyError
'numero'
如果我写m = request.POST.get('numero')，在命令行中我有：
...
My form html:
My Number: 7
m = 7
...
while len(lista) < m:
TypeError: unorderable types: int() < str()
EDIT :ModelForm 部分已删除，无需将数据保存在数据库中，因此使用经典表单：
方法一：使用 Django 的无模型经典表单
in your forms.py
from django import forms
class InputNumeroForm(forms.Form):
numero = forms.IntegerField()
in your views.py
from django.shortcuts import render
def stream_response(request):
form = InputNumeroForm()
if request.method == 'POST':
form = InputNumeroForm(data=request.POST)
if form.is_valid():
#Accessing the data in cleaned_data
m = form.cleaned_data['numero']
print "My Number %s" % m #watch your command line
resp = StreamingHttpResponse(stream.streamx(m))
return resp
#If not post provide the form here in the template :
return render(request, 'homepage/provadata.html', {
'form': form,
})
在你的模板中：
<form id="streamform" action="{% url 'stream_response' %}" method="POST">
{% csrf_token %}
{{ form }}
<input type="submit" value="to view" id="streambutton" />
</form>
为了澄清一点，Django 有两种类型的表单：
在这里，您不需要将号码保存在数据库中，因此您可以使用经典形式：https://docs.djangoproject.com/en/1.8/topics/forms/
方法二：不使用 Django 表单 对于像您的案例这样非常简单的表格：
in views.py
from django.shortcuts import render
def stream_response(request):
if request.method == 'POST':
if request.POST.get('numero', False):
m = int(request.POST['numero'])
print "My Number %s" % m #watch your command line
resp = StreamingHttpResponse(stream.streamx(m))
return resp
return render(request, 'homepage/provadata.html')
在你的模板中：
<form id="streamform" action="{% url 'stream_response' %}" method="POST">
{% csrf_token %}
<input type="number" name="numero" />
<input type="submit" value="to view" id="streambutton" />
</form>