必须有人怜悯这个人和他的同学。如果“just call printf”不是作弊，那么使用它也不应该是作弊。这是我从我遇到的第一个汇编程序中偷来的。它使用 DOS 中断来查找磁盘大小并打印dx:ax每三位数字有一个逗号。你们可能不需要逗号。我已经修改它很多年了 - 可能会做一个rdx:rax版本很快。非常适合显示阶乘。这是非常幼稚和低效的，但仍然有效。请随意改进它。当然，在缓冲区中获得字符后，它只是带有不同歌词的“Hello World”。
;-----------------------------------------------
; u64toda - converts (64 bit) integer in edx:eax
; to (comma delimited) decimal representation in
; zero (was "$") terminated string in buffer pointed to by edi
;----------------------------------------
u64toda:
pusha
mov ebx, edx ; stash high dword
mov esi,0Ah ; prepare to divide by 10
xor ecx, ecx ; zero the digit count
jmp highleft ; check is high word 0 ?
highword:
xchg eax,ebx ; swap high & low words
xor edx,edx ; zero edx for the divide!
div esi ; divide high word by 10
xchg eax,ebx ; swap 'em back
div esi ; divide low word including remainder
push edx ; remainder is our digit - save it
inc ecx ; count digits
highleft:
or ebx,ebx
jnz highword
lowleft:
xor edx,edx ; zero high word
div esi ; divide low word by 10
push edx ; our digit
inc ecx ; count it
or eax,eax ; 0 yet ?
jne lowleft
cmp ecx, byte 4 ; commas needed ?
jl write2buf ; nope
xor edx,edx ; zero high word for divide
mov eax,ecx ; number of digits
mov ebx,3
div ebx
mov esi,edx ; remainder = number digits before comma
test edx,edx
jnz write2buf ; no remainder?
mov esi,3 ; we can write 3 digits, then.
write2buf:
pop eax ; get digit back - in right order
add al,30H ; convert to ascii character
stosb ; write it to our buffer
dec esi ; digits before comma needed
jnz moredigits ; no comma needed yet
cmp ecx,2 ; we at the end?
jl moredigits ; don't need comma
mov al,',' ; write a comma
stosb
mov esi,03h ; we're good for another 3 digits
moredigits:
loop write2buf ; write more digits - cx of 'em
mov al,00h ; terminate buffer with zero
stosb
popa
ret
;------------------------
