当您没有类的源代码时，是否可以对对象进行 .NET 二进制序列化？

我在用BinaryFormatter在 C# 中对某些对象进行二进制序列化。但是，某些对象包含我通过 DLL 访问的类，并且没有源代码，因此我无法使用Serializable属性。有没有一种直接的方法来序列化它们？我有一个解决方法，其中包括上课NoSource并创建一个新类SerializableNoSource其构造函数采用NoSource对象并从中提取我需要的所有信息，但它很hacky。还有更好的选择吗？

你可以创建一个序列化代理.

想象一下，我们在引用的程序集中定义了一个我们无法控制的类，如下所示：

public class Person
{
    public string Name { get; set; }
    public int Age { get; set; }
    public DriversLicense License;
}


// An instance of this type will be part of the object graph and will need to be 
// serialized also.
public class DriversLicense
{
    public string Number { get; set; }
}

为了序列化该对象，您需要为对象图中的每种类型定义一个序列化代理。

要创建序列化代理，您只需创建一个实现以下功能的类型：ISerializationSurrogate界面：

public class PersonSurrogate : ISerializationSurrogate
{
    /// <summary>
    /// Manually add objects to the <see cref="SerializationInfo"/> store.
    /// </summary>
    public void GetObjectData(object obj, SerializationInfo info, StreamingContext context)
    {
        Person person = (Person) obj;
        info.AddValue("Name", person.Name);
        info.AddValue("Age", person.Age);
        info.AddValue("License", person.License);
    }

    /// <summary>
    /// Retrieves objects from the <see cref="SerializationInfo"/> store.
    /// </summary>
    /// <returns></returns>
    public object SetObjectData(object obj, SerializationInfo info, StreamingContext context, ISurrogateSelector selector)
    {
        Person person = (Person)obj;
        person.Name = info.GetString("Name");
        person.Age = info.GetInt32("Age");
        person.License = (DriversLicense) info.GetValue("License", typeof(DriversLicense));
        return person;
    }
}

public class DriversLicenseSurrogate : ISerializationSurrogate
{
    /// <summary>
    /// Manually add objects to the <see cref="SerializationInfo"/> store.
    /// </summary>
    public void GetObjectData(object obj, SerializationInfo info, StreamingContext context)
    {
        DriversLicense license = (DriversLicense)obj;
        info.AddValue("Number", license.Number);
    }

    /// <summary>
    /// Retrieves objects from the <see cref="SerializationInfo"/> store.
    /// </summary>
    /// <returns></returns>
    public object SetObjectData(object obj, SerializationInfo info, StreamingContext context, ISurrogateSelector selector)
    {
        DriversLicense license = (DriversLicense)obj;
        license.Number = info.GetString("Number");
        return license;
    }
}

那么你需要让你的IFormatter通过定义和初始化来了解代理SurrogateSelector并将其分配给您的IFormatter.

private static void SerializePerson(Person person)
{
    if (person == null)
        throw new ArgumentNullException("person");

    using (var memoryStream = new MemoryStream())
    {
        //Configure our surrogate selectors.
        var surrogateSelector = new SurrogateSelector();
        surrogateSelector.AddSurrogate(typeof (Person), new StreamingContext(StreamingContextStates.All),
                                       new PersonSurrogate());
        surrogateSelector.AddSurrogate(typeof (DriversLicense), new StreamingContext(StreamingContextStates.All),
                                       new DriversLicenseSurrogate());

        //Serialize the object
        IFormatter formatter = new BinaryFormatter();
        formatter.SurrogateSelector = surrogateSelector;
        formatter.Serialize(memoryStream, person);

        //Return to the beginning of the stream
        memoryStream.Seek(0, SeekOrigin.Begin);

        //Deserialize the object
        Person deserializedPerson = (Person) formatter.Deserialize(memoryStream);
    }
}

使用序列化代理绝不是简单的，并且当您尝试序列化的类型具有需要序列化的私有和受保护字段时，实际上可能会变得非常冗长。

但由于您已经手动序列化所需的值，我认为这不是问题。使用代理是处理此类场景的更统一的方式，应该会让您感觉更舒服。