这是我的代码,它连接四个 wav 文件并生成 wavAppend.wav。这个串联的文件可以在 Windows Media Player 中很好地播放。
但通过PlaySound类,只能听到one.wav。
有人可以帮忙吗?
class PlaySound extends Object implements LineListener
{
File soundFile;
JDialog playingDialog;
Clip clip;
public void PlaySnd(String s) throws Exception
{
JFileChooser chooser = new JFileChooser();
soundFile = new File(s);
Line.Info linfo = new Line.Info(Clip.class);
Line line = AudioSystem.getLine(linfo);
clip = (Clip) line;
clip.addLineListener(this);
AudioInputStream ais = AudioSystem.getAudioInputStream(soundFile);
clip.open(ais);
clip.start();
}
public void update(LineEvent le)
{
LineEvent.Type type = le.getType();
playingDialog.setVisible(false);
clip.stop();
clip.close();
}
}
public class Main
{
public static void main(String[] args)
{
int i;
String wavFile[] = new String[4];
wavFile[0] = "D://one.wav";
wavFile[1] = "D://two.wav";
wavFile[2] = "D://three.wav";
wavFile[3] = "D://space.au";
AudioInputStream appendedFiles;
try
{
AudioInputStream clip0=AudioSystem.getAudioInputStream(new File(wavFile[0]));
AudioInputStream clip1=AudioSystem.getAudioInputStream(new File(wavFile[1]));
AudioInputStream clip3;
for (i=0;i<4;i++)
{
appendedFiles = new AudioInputStream(
new SequenceInputStream(clip0, clip1),
clip0.getFormat(),
clip0.getFrameLength() + clip1.getFrameLength());
AudioSystem.write(appendedFiles, AudioFileFormat.Type.WAVE, new File("D:\\wavAppended.wav"));
clip3 = AudioSystem.getAudioInputStream(new File("D:\\wavAppended.wav"));
clip0=clip3;
clip1 = AudioSystem.getAudioInputStream(new File(wavFile[i+2]));
}
PlaySound p = new PlaySound();
p.PlaySnd("D://wavAppended.wav");
}
catch (Exception e)
{
e.printStackTrace();
}
}
}
WAV 文件不是这样工作的——您不能将多个文件放在一起(例如,就像您不能连接 JPEG 图像一样),因为数据上有一个标头,并且数据有多种不同的格式可能在。我很惊讶该文件竟然加载了。
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