我在以“laravel 方式”添加具有多个联合的查询时遇到问题。
我正在尝试完成一个与以下生成的查询等效的查询:
$ipsql = "";
for ($n = 1; $n < $total_networks; $n++) {
$ipsql .= "(SELECT * FROM ip WHERE network = " . $n . " AND used = 0 LIMIT 5)
UNION ALL";
}
if ($n == $total_networks) {
$ipsql .= "(SELECT * FROM ip WHERE network = " . $n . " AND used = 0 LIMIT 3) ORDER BY ip_addr";
}
我还没有找到与 Eloquent 联合的选项,因此我尝试对这个特定部分使用查询构建器,但在使用构建器 unionAll 时我不断遇到问题。
使用这个:
$ip_list = DB::table('ips')->where('network', '=', '0')->where('used', '=', '0')->limit(5);
for($n = 1; $n < $network_count; $n++){
$ip_list = DB::table('ips')->where('network', '=', $n)->where('used', '=', '0')->limit(5)->unionAll($ip_list);
}
$ips = $ip_list->get();
我不断收到 MySQL 语法错误:
SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax;
check the manual that corresponds to your MySQL server version for the right syntax to use near
'union all ((select * from `ips` where `network` = ? and `used` = ? limit 5) unio' at line 1
(SQL:
(select * from `ips` where `network` = 16 and `used` = 0 limit 5) union all ((select * from `ips`
where `network` = 15 and `used` = 0 limit 5) union all ((select * from `ips` where `network` = 14
and `used` = 0 limit 5) union all ((select * from `ips` where `network` = 13 and `used` = 0 limit 5)
union all ((select * from `ips` where `network` = 12 and `used` = 0 limit 5) union all ((select *
from `ips` where `network` = 11 and `used` = 0 limit 5) union all ((select * from `ips` where
`network` = 10 and `used` = 0 limit 5) union all ((select * from `ips` where `network` = 9 and
`used` = 0 limit 5) union all ((select * from `ips` where `network` = 8 and `used` = 0 limit 5)
union all ((select * from `ips` where `network` = 7 and `used` = 0 limit 5) union all ((select * from
`ips` where `network` = 6 and `used` = 0 limit 5) union all ((select * from `ips` where `network` =
5 and `used` = 0 limit 5) union all ((select * from `ips` where `network` = 4 and `used` = 0 limit
5) union all ((select * from `ips` where `network` = 3 and `used` = 0 limit 5) union all ((select *
from `ips` where `network` = 2 and `used` = 0 limit 5) union all ((select * from `ips` where
`network` = 1 and `used` = 0 limit 5) union all (select * from `ips` where `network` = 0 and `used`
= 0 limit 5)))))))))))))))))
我从错误中可以看出,它嵌套了每个新的联合调用,这导致了语法问题。
我尝试使用 DB::raw 完成相同的任务,但似乎也在某个地方犯了错误。有没有一种更适合 Laravel 的方法来实现这一点?
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