MySQL - 如何限制每个 ID 一个结果？

我有以下查询，它创建一个视图表，显示商店中最高的销售人员以及其他一些详细信息：

CREATE OR REPLACE VIEW sales_data AS 
SELECT s.storename AS "Store", 
       e.employee_name AS "Employee", 
       e1.employee_name AS "Manager", 
       SUM(p.total_sale_value) AS "Sales Value" 
FROM fss_Shop s 
       JOIN Employee e ON e.storeid = s.storeid 
       JOIN Payment p ON p.employee_number = e.employee_number 
       JOIN Employee e1 ON e1.employee_number = e.manager_number 
WHERE s.storeid=1 
GROUP BY e.employee_name 
ORDER BY SUM(p.total_sale_value) DESC LIMIT 1; 

上面的查询只会显示单个商店的销售数据，原因正如我所说WHERE s.storeid=1。我的表中有 20 家商店。如何更改上述查询，以便它为我提供 20 家商店的销售数据（即 20 行）。

CREATE OR REPLACE VIEW employee_sales_totals AS
    SELECT
        e.*,
        SUM(p.total_sale_value)   AS total_sale_value
    FROM
        Employee e
    INNER JOIN
        Payment  p
            ON p.employee_number = e.employee_number 
    GROUP BY
        e.id  -- This should be the Primary Key / Surrogate Key of the employee table
;

CREATE OR REPLACE VIEW shop_top_employee_by_sales_value AS
    SELECT
        s.storename          AS "Store", 
        e.employee_name      AS "Employee", 
        m.employee_name      AS "Manager", 
        p.total_sale_value   AS "Sales Value" 
    FROM
    (
        SELECT storeid, MAX(total_sale_value) AS total_sale_value
          FROM employee_sales_totals
      GROUP BY storeid
    )
       p
    INNER JOIN
        employee_sales_totals   e
            ON  e.storeid          = p.storeid
            AND e.total_sale_value = p.total_sale_value
    INNER JOIN
        fss_Shop   s 
            ON s.storeid = e.storeid 
    INNER JOIN
        Employee   m
            ON m.employee_number = e.manager_number 
;

根据您上一个问题的答案，如果同一家商店中有多名员工获得相同的总销售额，则所有这些员工都将被退回。