我在 swift 3 中有以下代码:
class StringUtility {
static func Localizer(tableName: String?) -> (_ key: String, _ params: CVarArg...) -> String {
return { (key: String, params: CVarArg...) in
let content = NSLocalizedString(key, tableName: tableName, comment: "")
if params.isEmpty {
return content
}
print(params) ->>>>>> this prints [[[Wells Fargo]]]
return NSString.init((format: content, arguments: getVaList(params))) as String
}
}
}
func localizationHelper(tableName: String, key: String, params: CVarArg...) -> String {
let t = StringResourceUtility.Localizer(tableName: tableName)
print(params) - >>>>>>>>>> this prints [[Wells Fargo]]
return t(key, params)
}
如果您在上面两个函数中看到 print 语句,则每次在函数内部传递 CVarArg 时都会附加 [] ,从而导致输出错误的本地化字符串。
1) CVarArg 不能像上面的代码一样多次传递?
2)如何解决这个问题?
您不能将变量参数列表传递给另一个函数,您
必须通过一个CVaListPointer
反而。还withVaList
应该
用来代替getVaList
:
class StringResourceUtility {
static func Localizer(tableName: String?) -> (_ key: String, _ params: CVaListPointer) -> String {
return { (key: String, params: CVaListPointer) in
let content = NSLocalizedString(key, tableName: tableName, comment: "")
return NSString(format: content, arguments: params) as String
}
}
}
func localizationHelper(tableName: String, key: String, params: CVarArg...) -> String {
let t = StringResourceUtility.Localizer(tableName: tableName)
return withVaList(params) { t(key, $0) }
}
Example:
let s = localizationHelper(tableName: "table", key: "%@ %@", params: "Wells", "Fargo")
print(s) // Wells Fargo
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