sample data from dataframe:

Pairs

(8, 8), (8, 8), (8, 8), (8, 8), (8, 8)
(6, 7), (7, 7), (7, 7), (7, 6), (6, 7)
(2, 12), (12, 3), (3, 4), (4, 12), (12, 12)

    ```
    
        new_col = []
            for e in content.Pairs:
            new_col.append(list(dict.fromkeys(e)))
            content['Unique'] = new_col
    
    ```

预期输出是 Pair 列中的唯一对，如下所示：

(8, 8),(6, 7),(7, 6),(7, 7),(2, 12) so on

尝试上面的代码时我得到的是这个结果：

Unique

['8', '']
['6', '7', '']
['2', '12', '3', '4', '']

如果我使用手动数据，那么数据有什么问题，那么它可以工作，为什么不在数据框中

你可以使用set method:

data = (((8, 8), (8, 8), (8, 8), (8, 8), (8, 8)),
  ((6, 7), (7, 7), (7, 7), (7, 6), (6, 7)),
  ((2, 12), (12, 3), (3, 4), (4, 12), (12, 12)))

uniques = []

for col in data:
  for unique in list(set(col)):
    uniques.append(unique)

for x in uniques:
  print(x)

OR:

data = (((8, 8), (8, 8), (8, 8), (8, 8), (8, 8)),
  ((6, 7), (7, 7), (7, 7), (7, 6), (6, 7)),
  ((2, 12), (12, 3), (3, 4), (4, 12), (12, 12)))

uniques = []

for col in data:
  uniques += [unique for unique in list(set(col))]

for x in uniques:
  print(x)