MySQL 查询使用 CASE 来 SELECT 多列

我有以下可以正确运行的查询：

SELECT Future.enemy_type,
CASE WHEN Future.enemy_type = 'square' THEN Users.color
ELSE ''
END AS color,
CASE WHEN Future.enemy_type = 'square' THEN Users.user_ID
ELSE ''
END AS ID,
CASE WHEN Future.enemy_type = 'headquarters' THEN Users.username
ELSE ''
END AS username,
CASE WHEN Future.enemy_type = 'headquarters' THEN Users.home_lat
ELSE ''
END AS lat
FROM Future
LEFT JOIN Users ON Future.user_ID_affected = Users.user_ID
WHERE Future.time > 1539503510
AND Future.time <= 1539503512
AND Future.user_ID = 10;

但是，有没有更高效的写法呢？我需要根据条件（例如广场或总部）选择一些值，但我知道 CASE 只能返回 1 个值。然而，每次我想返回一个值时都用新的 CASE 语句检查条件似乎效率很低。

SO 上的一些人建议对类似查询使用 JOIN 语句，但我不确定这如何与多个条件一起使用？

提前致谢。

我喜欢IF()简单语句的函数：

SELECT
    Future.enemy_type,
    IF (Future.enemy_type = 'square', Users.color, '') AS color,
    IF (Future.enemy_type = 'square', Users.user_ID, '') AS ID,
    IF (Future.enemy_type = 'headquarters', Users.username, '') AS username,
    IF (Future.enemy_type = 'headquarters', Users.home_lat, '') AS lat
FROM Future
LEFT JOIN Users
    ON Future.user_ID_affected = Users.user_ID
WHERE
    Future.time > 1539503510  AND
    Future.time <= 1539503512 AND
    Future.user_ID = 10;