从 python 集中获取唯一的元组

我目前有一套如下所示：

{(a,b), (b,a), (c,b), (b,c)}

我想要的是：

{(a,b), (c,b)}

您可能会注意到，重复值已被完全删除，因此无论顺序如何，两个元组内部永远不会有相同的元素。

如何告诉集合忽略元组中元素的顺序并仅检查元组之间的值？

好的，你已经有了一套{c1, c2, c3, ...}，其中每个cN本身就是某种集合。

If you don't care about the order of the elements in cN, but do care that it is unique (disregarding order), then cN should be a frozenset¹ rather than a tuple:

>>> orig = {("a", "b"), ("b", "a"), ("c", "b"), ("b", "c")}
>>> uniq = {frozenset(c) for c in orig}
>>> uniq
{frozenset(['b', 'a']), frozenset(['b', 'c'])}

一般来说，从 Python 提供的数据类型中选择合适的数据类型比定义和维护自定义类更简单。

¹ It can't be a set, because as a member of a larger set it needs to be hashable.