从列表python的单个列表中删除子列表

我已经经历过从列表列表中删除子列表 https://stackoverflow.com/questions/47209786/removing-sublists-from-a-list-of-lists，但当我为我的数据集扩展它时，它不适用于我的情况。因此发布一个新问题。

list1=[['A,C,D', 'Y', 'hello'],
['A,B,D', 'Y', 'hello'],
['B,C,D', 'Y', 'hello'],
['A,B,C,D', 'Y', 'hello'],
['A', 'Z', 'hello'],
['A,C', 'Z', 'hello'],
['B,C', 'Z', 'hello'],
['A,C', 'Z', 'hello'],
['A,B,C', 'Z', 'hello'],
['H,I,J,K', 'Z', 'hello'],
['H,K', 'Z', 'hello'],
['H,L', 'Z', 'hello'],
['I,J,K,L', 'Z', 'hello'],
['H,I,J,K,L', 'Z', 'hello'],
['B,C,D','Z','hi'],
['A,D,C,B','Z','hi']]

我想删除一些元素并在下面发布所需的输出：

**Output**
[['A,B,C,D', 'Y', 'hello'],
 ['A,B,C', 'Z', 'hello'],
 ['H,I,J,K,L', 'Z', 'hello'],
 ['A,D,C,B','Z','hi']]

我尝试过以下代码：

sets = [set(l) for l in lists]
new_list = [l for l,s in zip(lists, sets) if not any(s < other for other in sets)]

你必须将所有的分开,子列表中的所有元素都比您可以使用的solution https://stackoverflow.com/questions/47209786/removing-sublists-from-a-list-of-lists你已经发现：

st = [{i for e in l for i in e.split(',') } for l in list1]
[l for l, s in zip(list1, st) if not any(s < other for other in st)]

output:

[['A,B,C,D', 'Y', 'hello'],
 ['A,B,C', 'Z', 'hello'],
 ['H,I,J,K,L', 'Z', 'hello'],
 ['A,D,C,B', 'Z', 'hi']]