python http请求和响应是如何工作的

我是 python 新手，我有任务，所以我需要扫描 wifi 并将数据发送到服务器，下面是我必须发送的格式，在浏览器 url 文本框中手动输入时可以正常工作，

http://223.56.124.58:8080/ppod-web/ProcessRawData?data={"userId":"2220081127-14","timestamp":"2010-04-12 10:54:24","wifi":{"ssid":"guest","rssi":"80"}}

这是我的代码：

import httplib  
import urllib

params = urllib.urlencode('{\"userId\":\"20081127-14\",\"timestamp\":\"2010-04-12 10:54:24\",\"wifi\":{\"ssid\":\"guest\",\"rssi\":\"80\"}}')

headers = {"Content-type":"application/x-www-form-urlencoded","Accept":"text/plain"}
conn = httplib.HTTPConnection("http://223.56.124.58:8080")
conn.request("POST","ppod-web/ProcessRawData?data=",params,headers)
response = conn.getresponse()   
print response.status  
print "-----"  
print response.reason  
data = response.read()   
print data
conn.close()

thanks

最有可能的是，这个问题使用您在问题中发布的脚本你不能直接做：

conn=httplib.HTTPConnection("http://223.56.124.58:8080/wireless") 

异常触发于getaddrinfo() http://docs.python.org/library/socket.html#socket.getaddrinfo，它调用 C 函数getaddrinfo() http://linux.die.net/man/3/getaddrinfo返回EAI_NONAME:

节点或服务未知；或者节点和服务都为NULL；或者在hints.ai_flags中指定了AI_NUMERICSERV，并且服务不是数字端口号字符串。”

显然是传递的参数有问题getaddrinfo，并且很可能您正在尝试获取有关"223.56.124.58:8080/wireless"主持人。哎呀！

事实上，您无法直接连接到 URL 地址。正如文档清楚地说明和显示的那样 http://docs.python.org/library/httplib.html#httplib.HTTPConnection，您连接到server:

conn = httplib.HTTPConnection("223.56.124.58", 8080)

然后你可以这样做：

conn.request("POST", "wireless", params, headers)

关于什么你是脚本actually using?

conn.request("POST","http://202.45.139.58:8080/ppod-web",params,headers)

即使连接正确形成，您也会 POSTing 到http://202.45.139.58:8080/http://202.45.139.58:8080/ppod-web。你真正想要的可能是：

conn = httplib.HTTPConnection("202.45.139.58", 8080)
conn.request("POST", "ppod-web", params, headers)

该行显示错误是因为很可能HTTPConnection是一个惰性对象，仅在调用时尝试实际连接到服务器request().

完成上述修复后，您需要修复params.

>>> urllib.urlencode({"wifi":{"ssid":"guest","rssi","80"}})
SyntaxError: invalid syntax
>>> urllib.urlencode({"wifi":{"ssid":"guest","rssi":"80"}})
'wifi=%7B%27rssi%27%3A+%2780%27%2C+%27ssid%27%3A+%27guest%27%7D'

To get what you think you want to get, you should do:

>>> urllib.urlencode({"data": {"wifi":{"ssid":"guest","rssi":"80"}}})
'data=%7B%27wifi%27%3A+%7B%27rssi%27%3A+%2780%27%2C+%27ssid%27%3A+%27guest%27%7D%7D'