如何使用 __getattr__ 来制作可供选择的课程

如何修改下面的类以使其可供选择？

这个问题：如何使 __getattr__ 可以正确选择的类？ https://stackoverflow.com/questions/42272335/how-to-make-a-class-which-has-getattr-properly-pickable类似，但在使用中引用了错误的异常getattr.

这另一个问题似乎提供了有意义的见解为什么 pickle.dumps 调用 __getattr__ ？ https://stackoverflow.com/questions/12101574/why-does-pickle-dumps-call-getattr，但是它未能提供示例，而且我真的无法理解我应该实现什么。

import pickle
class Foo(object):
    def __init__(self, dct):
        for key in dct:
            setattr(self, key, dct[key])


class Bar(object):
    def __init__(self, dct):
        for key in dct:
            setattr(self, key, dct[key])

    def __getattr__(self, attr):
        """If attr is not in channel, look in timing_data
        """
        return getattr(self.foo, attr)

if __name__=='__main__':
    dct={'a':1,'b':2,'c':3}
    foo=Foo(dct)
    dct2={'d':1,'e':2,'f':3,'foo':foo}
    bar=Bar(dct2)
    pickle.dump(bar,open('test.pkl','w'))
    bar=pickle.load(open('test.pkl','r'))

Results:

     14         """If attr is not in channel, look in timing_data
     15         """
---> 16         return getattr(self.foo, attr)
     17
     18 if __name__=='__main__':

RuntimeError: maximum recursion depth exceeded while calling a Python object

这里的问题是你的__getattr__方法执行得不好。它假设self.foo存在。如果self.foo不存在，尝试访问它最终会调用__getattr__- 这会导致无限递归：

>>> bar = Bar({})  # no `foo` attribute
>>> bar.x
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "untitled.py", line 19, in __getattr__
    return getattr(self.foo, attr)
  File "untitled.py", line 19, in __getattr__
    return getattr(self.foo, attr)
  File "untitled.py", line 19, in __getattr__
    return getattr(self.foo, attr)
  [Previous line repeated 329 more times]
RecursionError: maximum recursion depth exceeded while calling a Python object

要解决此问题，如果没有，则必须抛出 AttributeErrorfoo属性存在：

def __getattr__(self, attr):
    """If attr is not in channel, look in timing_data
    """
    if 'foo' not in vars(self):
        raise AttributeError
    return getattr(self.foo, attr)

（我用的是vars https://docs.python.org/3/library/functions.html#vars函数来获取对象的字典，因为它看起来比self.__dict__.)

现在一切都按预期进行：

dct={'a':1,'b':2,'c':3}
foo=Foo(dct)
dct2={'d':1,'e':2,'f':3,'foo':foo}
bar=Bar(dct2)
data = pickle.dumps(bar)
bar = pickle.loads(data)
print(vars(bar))
# output:
# {'d': 1, 'e': 2, 'f': 3, 'foo': <__main__.Foo object at 0x7f040fc7e7f0>}