您可以使用itertools.groupby
:
>>> from itertools import groupby
>>> from operator import itemgetter
>>> lis = [[10, 0], [30, 0], [40, 2], [20, 2], [90, 0], [80, 0]]
>>> [list(g) for k,g in groupby(lis, key=itemgetter(1))]
[[[10, 0], [30, 0]],
[[40, 2], [20, 2]],
[[90, 0], [80, 0]]]
对于第二个:
>>> ans = []
for k,g in groupby(lis, key=itemgetter(1)):
l = list(g)
ans.append(l)
if len(ans) > 1:
ans[-2].append(l[0])
...
>>> ans
[[[10, 0], [30, 0], [40, 2]],
[[40, 2], [20, 2], [90, 0]],
[[90, 0], [80, 0]]]
Update:
>>> from itertools import zip_longest
>>> lis = [[[10, 0], [30, 0]],
[[40, 2], [20, 2]],
[[90, 0], [80, 0]]]
>>> [x + ([y[0]] if y else []) for x,y in
zip_longest(lis,lis[1:])]
[[[10, 0], [30, 0], [40, 2]],
[[40, 2], [20, 2], [90, 0]],
[[90, 0], [80, 0]]]