我在循环和声明变量方面遇到问题。目前我正在制作一个关于 Collatz 猜想的程序，该程序应该检查从一定数量的 Collatz 序列中到达一个的最大步骤是什么。这是我的代码：
start_num = int(input("insert a starting Number > "))
how_many = int(input("how many times you want to check? >"))
def even_or_odd(number):
if number % 2 == 0:
return 'isEven'
else:
return 'notEven'
def collatz(n):
z = n
counter = 0
while True:
if n != 1:
if even_or_odd(n) == 'isEven':
n = n/2
counter += 1
continue
if even_or_odd(n) == 'notEven':
n = (n*3)+1
counter += 1
continue
else:
print('number ' + str(z) + ' reached 1 with : ' + str(counter) + ' steps')
return counter
break
def check_biggest_steps(steps_before, steps_after):
if steps_before > steps_after:
return steps_before
if steps_after > steps_before:
return steps_after
if steps_after == steps_before:
return steps_after
def compute_collatz(n_times, collatz_number):
for _ in range(n_times):
before = collatz(collatz_number)
collatz_number += 1
after = collatz(collatz_number)
collatz_number += 1
biggest_steps = check_biggest_steps(before, after)
print('Biggest Steps is :' + str(biggest_steps))
compute_collatz(how_many, start_num)
this biggest_steps变量始终返回最后 2 个步骤。我知道造成这个问题的原因是biggest_step变量位于循环内，但我无法让它在任何地方工作，不知道该怎么做。谢谢
在您亲自尝试之前，请不要阅读我的代码。
尝试创建一个列表，将每个更改附加到列表中，然后要获取最后的移动次数，只需获取列表的长度即可。
.
def collatz(x):
while x != 1:
if x % 2 > 0:
x =((3 * x) + 1)
list_.append(x)
else:
x = (x / 2)
list_.append(x)
return list_
print('Please enter a number: ', end='')
while True:
try:
x = int(input())
list_ = [x]
break
except ValueError:
print('Invaid selection, try again: ', end='')
l = collatz(x)
print('\nList:', l, sep=' ')
print('Number of steps required:', len(l) - 1)
本文内容由网友自发贡献，版权归原作者所有，本站不承担相应法律责任。如您发现有涉嫌抄袭侵权的内容，请联系:hwhale#tublm.com(使用前将#替换为@)
