如何将 PHP 中的数据插入到 MariaDB 中？

我熟悉 MySql 数据库，但有一个名为 MariaDB 的新数据库。我尝试从 PHP 代码插入数据但不能，那么你能帮我插入数据吗？我的服务器上的 PHP 版本是 5.4.32，MySQL 版本是 10.0.20-MariaDB-cll-live。

这是我用来尝试将数据插入 MariaDB 的代码。

$connection = mysql_connect("localhost", "root", ""); // Establishing Connection with Server
$db = mysql_select_db("database", $connection); // Selecting Database from Server

if(isset($_POST['submit'])){ // Fetching variables of the form which travels in URL
    $name = $_POST['name'];
    $email = $_POST['email'];
    if($name !=''||$email !=''){
       //Insert Query of SQL
       $query = mysql_query("insert into VIP Membership(Name, Email) values ('$name', '$email')");
       echo "<br/><br/><span>Data Inserted successfully...!!</span>";
    }
    else{
       echo "<p>Insertion Failed <br/> Some Fields are Blank....!!</p>";
    }
}

mysql_close($connection); // Closing Connection with Server

编辑：我现在使用 mysqli 代码，但它向我抛出错误 500。

<?php
$servername = "localhost";
$username = "username";
$password = "";
$dbname = "db_table";

// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
}
if(isset($_POST['submit'])){ // Fetching variables of the form which travels in URL
$name = $_POST['name'];
$email = $_POST['email'];
if($name !=''||$email !=''){

$sql = "INSERT INTO 'VIP Membership' (Name, Email)
VALUES ('$name', '$email')";

if(mysqli_query($conn, $sql)) {
    echo "New record created successfully";
} else {
    echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}
}

mysqli_close($conn);

你需要使用反引号（不是单引号）将您的表名称括起来，因为其中有一个空格。

$sql = "INSERT INTO `VIP Membership` (Name, Email) VALUES ('$name', '$email')";

更新：你应该really使用准备好的语句。就目前而言，这段代码非常不安全。

$sql = mysqli_prepare($conn, "INSERT INTO `VIP Membership` (Name, Email) VALUES (?, ?)");
if($sql !== FALSE){
    mysqli_stmt_bind_param($sql, "ss", $name, $email);
    if(mysqli_stmt_execute($sql)){
        echo "New record created successfully";
    } else {
        echo mysqli_stmt_error($sql);
    }
} else{
    echo mysqli_error($conn);
}