我在 stackoverflow 中发现了类似的查询,但没有找到解决方案。所以我再问一遍。我有以下内容insert
query :
$purchase_date = date("Y-m-d");
$init = substr($info[fname], 0, 2);
$odr = rand(0,255);
$invoice_number = $this->get_invoice_number();
//$invoice_number = $invoice_number+1;
//$invoice_number = 400 + rand(0,100);
$order_number = $init.'-'.$odr;
$session_id = session_id();
$sql = "
INSERT INTO
tbl_checkout
SET
fname = '$info[fname]',
lname = '$info[lname]',
email = '$info[email]',
phone = '$info[phone]',
address = '$info[address]',
pin = '$info[pin]',
session_id = '$session_id',
purchase_date = '$purchase_date',
invoice_number = '$invoice_number',
order_number = '$order_number' <----This is line no 1038
";
$this->db->insertQuery($sql);
但是当我尝试执行它时,它显示错误,例如Catchable fatal error: Object of class stdClass could not be converted to string in c:\.....on line 1038
我迷失了,因为我什至不明白错误的含义!请帮忙。
$this->get_invoice_number()
可能正在返回一个对象。
您可以将其转换为字符串:
$invoice_number = (string) $this->get_invoice_number();
本文内容由网友自发贡献,版权归原作者所有,本站不承担相应法律责任。如您发现有涉嫌抄袭侵权的内容,请联系:hwhale#tublm.com(使用前将#替换为@)