我正在尝试添加条件重试WebClient使用 Kotlin 协程 + WebFlux.fn +reactor-addons：
suspend fun ClientResponse.asResponse(): ServerResponse =
status(statusCode())
.headers { headerConsumer -> headerConsumer.addAll(headers().asHttpHeaders()) }
.body(bodyToMono(DataBuffer::class.java), DataBuffer::class.java)
.retryWhen {
Retry.onlyIf { ctx: RetryContext<Throwable> -> (ctx.exception() as? WebClientResponseException)?.statusCode in retryableErrorCodes }
.exponentialBackoff(ofSeconds(1), ofSeconds(5))
.retryMax(3)
.doOnRetry { log.error("Retry for {}", it.exception()) }
)
.awaitSingle()
还在重试之前添加一个条件
if (statusCode().isError) {
body(
BodyInserters.fromPublisher(
Mono.error(StatusCodeError(status = statusCode())),
StatusCodeException::class.java
)
)
} else {
body(bodyToMono(DataBuffer::class.java), DataBuffer::class.java)
}
调用看起来像：
suspend fun request(): ServerResponse =
webClient/*...*/
.awaitExchange()
.asResponse()
This spring webclient：在特定错误上进行回退重试 https://stackoverflow.com/questions/58520919/spring-webclient-retry-with-backoff-on-specific-error/58521233#58521233给了我回答问题的提示：
.awaitExchange()返回ClientResponse并不是Mono<ClientReponse>这意味着我的重试正在执行bodyToMono而不是操作exchange().
解决方案现在看起来像
suspend fun Mono<ClientResponse>.asResponse(): ServerResponse =
flatMap {
if (it.statusCode().isError) {
Mono.error(StatusCodeException(status = it.statusCode()))
} else {
it.asResponse()
}
}.retryWhen(
Retry.onlyIf { ctx: RetryContext<Throwable> ->
(ctx.exception() as? StatusCodeException)?.shouldRetry() ?: false
}
.exponentialBackoff(ofSeconds(1), ofSeconds(5))
.retryMax(3)
.doOnRetry { log.error { it.exception() } }
).awaitSingle()
private fun ClientResponse.asResponse(): Mono<ServerResponse> =
status(statusCode())
.headers { headerConsumer -> headerConsumer.addAll(headers().asHttpHeaders()) }
.body(bodyToMono(DataBuffer::class.java), DataBuffer::class.java)
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