我正在尝试显示当前用户的详细信息，但是我不断收到错误。我尝试从模板访问经过身份验证的用户，但这不起作用，因为我收到此错误：
在 org.springframework.security.core.userdetails.User 类型上找不到方法 getFirstName()
我试图从控制器获取信息，然后将其保存在字符串中并将该字符串传递给模板，但这也不起作用。
这是我的 SecurityConfig 类：
@Configuration
public class SecurityConfig extends WebSecurityConfigurerAdapter {
@Autowired
private UserService userService;
@Override
protected void configure(HttpSecurity http) throws Exception {
http
.authorizeRequests()
.antMatchers(
"/registration",
"/js/**",
"/css/**",
"/img/**",
"/webjars/**").permitAll()
.anyRequest().authenticated()
.and()
.formLogin()
.loginPage("/login")
.permitAll()
.and()
.logout()
.invalidateHttpSession(true)
.clearAuthentication(true)
.logoutRequestMatcher(new AntPathRequestMatcher("/logout"))
.logoutSuccessUrl("/login?logout")
.permitAll();
}
@Bean
public BCryptPasswordEncoder passwordEncoder(){
return new BCryptPasswordEncoder();
}
@Bean
public DaoAuthenticationProvider authenticationProvider(){
DaoAuthenticationProvider auth = new DaoAuthenticationProvider();
auth.setUserDetailsService(userService);
auth.setPasswordEncoder(passwordEncoder());
return auth;
}
@Override
protected void configure(AuthenticationManagerBuilder auth) throws Exception {
auth.authenticationProvider(authenticationProvider());
}
这是我的 UserService 类：
public interface UserService extends UserDetailsService {
User findByEmailAddress(String emailAddress);
// User findByFirstName(String firstName);
User save(UserRegistrationDto registration);
}
这是我的 UserServiceImpl 类：
@Service
public class UserServiceImpl implements UserService {
@Autowired
private UserRepository userRepository;
@Autowired
private BCryptPasswordEncoder passwordEncoder;
@Override
public UserDetails loadUserByUsername(String emailAddress) throws
UsernameNotFoundException {
User user = userRepository.findByEmailAddress(emailAddress);
if (user == null){
throw new UsernameNotFoundException("Invalid username or
password.");
}
return new
org.springframework.security.core.userdetails.User(user.getEmailAddress(),
user.getPassword(),
mapRolesToAuthorities(user.getRoles()));
}
public User findByEmailAddress(String emailAddress){
return userRepository.findByEmailAddress(emailAddress);
}
public User save(UserRegistrationDto registration){
User user = new User();
user.setFirstName(registration.getFirstName());
user.setSurname(registration.getSurname());
user.setEmailAddress(registration.getEmailAddress());
user.setPassword(passwordEncoder.encode(registration.getPassword()));
user.setRoles(Arrays.asList(new Role("ROLE_USER")));
return userRepository.save(user);
}
private Collection<? extends GrantedAuthority>
mapRolesToAuthorities(Collection<Role> roles){
return roles.stream()
.map(role -> new SimpleGrantedAuthority(role.getName()))
.collect(Collectors.toList());
}
}
这是模板类中的一些代码，我试图在其中获取信息：
th:text ="${#authentication.getPrincipal().getFirstName()}">
th:text ="${#authentication.getPrincipal().getUser().getFirstName()}">
这是登录控制器。我注释掉的部分是我试图获取当前用户详细信息的另一种方式：
@Controller
//@RequestMapping("/login")
public class MainController {
// @GetMapping("/")
// public String root() {
// return "userProfile1";
// }
@GetMapping("/login")
public String login(Model model) {
return "login";
}
// @GetMapping
// public String displayUserAccount(@ModelAttribute("user") @Valid
UserRegistrationDto userDto, BindingResult result, Model model) {
//
//
// model.addAttribute("firstName", ((UserRegistrationDto)
auth).getEmailAddress());
//
// model.addAttribute("emailAddress", userDto.getEmailAddress());
// model.addAttribute("firstName", userDto.getFirstName());
// model.addAttribute("surname", userDto.getSurname());
// model.addAttribute("age", userDto.getAge());
// model.addAttribute("gender", userDto.getGender());
// model.addAttribute("dob", userDto.getDob());
// // return "redirect:/registration?success";
// return "userProfile1";
//
// }
@ResponseBody
public String currentUserName(Authentication auth) {
((UserRegistrationDto) auth).getEmailAddress();
return "userProfile1";
}
}
这都是我很抱歉的地方！非常感谢任何提供帮助的人:D
