Mysql返回多行

我有这个疑问。

SELECT notes.id,enter.name as 'enter_name',step.title as 'flow status',notes.user_name as user_created,notes.created,notes.rel_client_id,td_doc_nr.value_string as 'document number',enter.enter_code,
    IF(!ISNULL(td_doc_nr.value_string),
     (SELECT  GROUP_CONCAT(product_name SEPARATOR ',') from notes d 
        join note_bundles b on b.note_id = d.id
        join note_products p on p.doc_bundle_id = b.id
        join note_product_get_fields f on f.doc_product_id = p.id
        join note_product_get_field_data fd on fd.get_field_id = f.id
        where d.doc_nr = td_doc_nr.value_string
        and value_string ='auto')
,NULL) as test
FROM notes notes
JOIN notes_steps step ON  step.id  = notes.step_id 
JOIN notes_enters enter ON enter.id = notes.enter_id
    LEFT JOIN notes_custom_fields tf_doc_nr ON tf_doc_nr.name = 'note_number' AND tf_doc_nr.rel_entity_id = enter.id
    LEFT JOIN notes_custom_field_data td_doc_nr ON td_doc_nr.rel_entity_id = notes.id AND
 td_doc_nr.field_instance_id = tf_doc_nr.id 
WHERE notes.enter_id in  (777) AND notes.status = 1  

我将此子查询添加到“if 语句”中

 SELECT  GROUP_CONCAT(product_name SEPARATOR ',') from nontes d 
    join note_bundles b on b.note_id = d.id
    join note_products p on p.doc_bundle_id = b.id
    join note_product_get_fields f on f.doc_product_id = p.id
    join note_product_get_field_data fd on fd.get_field_id = f.id
    where d.doc_nr = 'G7777777'
    and value_string ='auto'

之后我添加了一个新列。

 SELECT  GROUP_CONCAT(product_name SEPARATOR ','),GROUP_CONCAT(DISTINCT b.msisdn SEPARATOR ',') from notes d 
    join note_bundles b on b.note_id = d.id
    join note_products p on p.doc_bundle_id = b.id
    join note_product_get_fields f on f.doc_product_id = p.id
    join note_product_get_field_data fd on fd.get_field_id = f.id
    where d.doc_nr = 'G7777777'
    and value_string ='auto'

它返回两列。 如何返回两列？可能吗？ ：） 谢谢

IF 语句内的子查询不能返回多列。您需要将子查询加入到结果中，并分别取出两个单独的列：

SELECT ...
    IF(!ISNULL(td_doc_nr.value_string), sub.one, NULL) as one,
    IF(!ISNULL(td_doc_nr.value_string), sub.two, NULL) as two
FROM ...
LEFT JOIN (
    SELECT  d.doc_nr, GROUP_CONCAT(product_name SEPARATOR ','),GROUP_CONCAT(DISTINCT b.msisdn SEPARATOR ',') from documents d 
    join document_bundles b on b.document_id = d.id
    join document_products p on p.doc_bundle_id = b.id
    join document_product_cstm_fields f on f.doc_product_id = p.id
    join document_product_cstm_field_data fd on fd.cstm_field_id = f.id
    where value_string ='auto'
    group by d.doc_nr
) sub on sub.doc_nr = td_doc_nr.value_string