Backbone.js 与 Eco 模板:如何在模板中包含模板?

2023-12-27

是否可以在模板中包含模板?也许类似于 ERB 处理部分的方式?

与其尝试以 ERB 之类的方式渲染嵌套模型,不如让 Backbone.js 来处理这个问题。

注意,我使用的是 Coffeescript 语法:

项目.IndexView

template: JST["backbone/templates/projects/index"]

addAll: () ->
    @options.projects.each(@addOne)

addOne: (project) ->
    view = new Worktimer.Views.Projects.ProjectView({model : project})
    @$("#projects-table").append(view.render().el)

render: ->
    $(@el).html(@template(projects: @options.projects.toJSON() ))
    @addAll()

模型项目有一个名为会话的嵌套集合:

项目.项目视图

template: JST["backbone/templates/projects/project"]

$(@el).html(@template(@model.toJSON() ))     
for s in @model.sessions.models
    v = new Worktimer.Views.ProjectSessions.ShowView(model: s)
    $(@el).find('.sessions').append(v.render().el)

项目会话.ShowView

template: JST["backbone/templates/project_sessions/show"]

render: ->
    $(this.el).html(@template(@model.toJSON() ))

所以,最后我们有这样的嵌套模板:

  • Projects Index
    • Project
      • Session
      • Session
      • Session
      • Session
    • Project
      • Session
    • Project
      • Session
      • Session

这是我用于脊柱的小帮手:

# Render Partials in ECO-Templates like in Rails-ERB
# 
# usefull to clean up structure in spine.js and other js-mvc´s like backbone 
# 
# usage:
#   <%- render_partial 'path/to/partial' %>  ..  will render ../spine-app/views/path/to/_partial.jst.eco
#   <%- render_partial 'path/to/partial', foo: 'bar' %>  ..  will render ../spine-app/views/path/to/_partial.jst.eco  ..  locals = @foo 
#
window.render_partial = ( path, options = {} ) ->
    # add the leading underscore (like rails-partials)
    path = path.split('/')
    path[ path.length - 1 ] = '_' + path[ path.length - 1 ]
    path = path.join('/')
    # render and return the partial if existing
    try
        JST["app/views/#{ path }"]( options )
    catch error
        # if App.Environment != 'production' then "<p class='error'>Sorry, there is no partial named '#{ path }'.</p>" else ''
        "<p class='error'>Sorry, there is no partial named '#{ path }'.</p>"
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