有没有一种方法可以使用 libclang 检测匿名枚举而不依赖于拼写名称中的文本?
python 绑定到libclang https://raw.githubusercontent.com/llvm-mirror/clang/release_36/bindings/python/clang/cindex.py包含检测 C/C++ 结构或联合是否是匿名的功能clang.cindex.Cursor.is_anonymous https://github.com/llvm-mirror/clang/blob/release_37/bindings/python/clang/cindex.py#L1483,最终调用clang_Cursor_isAnonymous http://clang.llvm.org/doxygen/group__CINDEX__TYPES.html#ga6e0d2674d126fd43816ce3a80b592373.
以下示例演示了该问题。
import sys
from clang.cindex import *
def nodeinfo(n):
return (n.kind, n.is_anonymous(), n.spelling, n.type.spelling)
idx = Index.create()
# translation unit parsed correctly
tu = idx.parse(sys.argv[1], ['-std=c++11'])
assert(len(tu.diagnostics) == 0)
for n in tu.cursor.walk_preorder():
if n.kind == CursorKind.STRUCT_DECL and n.is_anonymous():
print nodeinfo(n)
if n.kind == CursorKind.UNION_DECL and n.is_anonymous():
print nodeinfo(n)
if n.kind == CursorKind.ENUM_DECL:
if n.is_anonymous():
print nodeinfo(n)
else:
print 'INCORRECT', nodeinfo(n)
当在sample.cpp上运行时
enum
{
VAL = 1
};
struct s
{
struct {};
union
{
int x;
float y;
};
};
Gives:
INCORRECT (CursorKind.ENUM_DECL, False, '', '(anonymous enum at sample1.cpp:1:1)')
(CursorKind.STRUCT_DECL, True, '', 's::(anonymous struct at sample1.cpp:8:5)')
(CursorKind.UNION_DECL, True, '', 's::(anonymous union at sample1.cpp:9:5)')