我正在关注this http://www.raywenderlich.com/30445/afnetworking-crash-course在 IOS 中学习 AfNetworking 的教程
我正在使用以下函数来获取服务器的响应:
{
// 1
NSString *weatherUrl = [NSString stringWithFormat:@"%@weather.php?format=json", BaseURLString];
NSURL *url = [NSURL URLWithString:weatherUrl];
NSURLRequest *request = [NSURLRequest requestWithURL:url];
// 2
AFJSONRequestOperation *operation =
[AFJSONRequestOperation JSONRequestOperationWithRequest:request
// 3
success:^(NSURLRequest *request, NSHTTPURLResponse *response, id JSON) {
//Success
}
// 4
failure:^(NSURLRequest *request, NSHTTPURLResponse *response, NSError *error, id JSON) {
UIAlertView *av = [[UIAlertView alloc] initWithTitle:@"Error Retrieving Weather"
message:[NSString stringWithFormat:@"%@",error]
delegate:nil
cancelButtonTitle:@"OK" otherButtonTitles:nil];
[av show];
}];
// 5
[operation start];
}
我想要的是编写一个函数,它将返回响应NSString
得到回应后。我不知道语法。有人可以帮助我吗?
Try this
- (void)getResponse:(void (^)(id result, NSError *error))block {
NSString *weatherUrl = [NSString stringWithFormat:@"%@weather.php?format=json", BaseURLString];
NSURL *url = [NSURL URLWithString:weatherUrl];
NSURLRequest *request = [NSURLRequest requestWithURL:url];
// 2
AFJSONRequestOperation *operation =
[AFJSONRequestOperation JSONRequestOperationWithRequest:request
// 3
success:^(NSURLRequest *request, NSHTTPURLResponse *response, id JSON) {
//Success
block(JSON,nil); //call block here
}
// 4
failure:^(NSURLRequest *request, NSHTTPURLResponse *response, NSError *error, id JSON) {
UIAlertView *av = [[UIAlertView alloc] initWithTitle:@"Error Retrieving Weather"
message:[NSString stringWithFormat:@"%@",error]
delegate:nil
cancelButtonTitle:@"OK" otherButtonTitles:nil];
[av show];
}];
// 5
[operation start];
}
calling
[self getResponse:^(id result, NSError *error) {
//use result here
}];
希望这可以帮助
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