我在保存数据输出后遇到问题foreach loop
这是读取我的数据并处理它的函数
readFiles <- function(x){
data <- read.table("filelist",
skip=grep('# Begin: Data Text', readLines(filelist)),
na.strings=c("NA", "-", "?"),
colClasses="numeric")
my <- as.matrix(data[1:57600,2]);
mesh <- array(my, dim = c(120,60,8));
Ms <- 1350*10^3 # A/m
asd2 <- (mesh[70:75,24:36 ,2])/Ms; # in A/m
ort_my <- mean(asd2);
return(ort_my)
}
这是进行并行处理的代码
#R Code to run functions in parallel
detectCores() #This will tell you how many cores are available
library("foreach");
library("parallel");
library(doParallel)
#library("doMC") this is for Linux
#registerDoMC(12) #Register the parallel backend
cl<-makeCluster(4)
registerDoParallel(cl) # Register 12 cpu for the parallel backend
OutputList <- foreach(i=1:length(filelist),
.combine='c', .packages=c("data.table")) %dopar% (readFiles)
#registerDoSEQ() #Very important to close out parallel backend.
aa<-OutputList
stopCluster(cl)
print(Sys.time()-strt)
write.table(aa, file="D:/ads.txt",sep='\t')
一切都很顺利，但是当我检查时OutputList我只看到的function(x)我想写ort_my对于文件列表中的每个文件。
这是我所看到的
[[70]]
function (x)
{
data <- read.table("filelist", skip = grep("# Begin: Data Text",
readLines(filelist)), na.strings = c("NA", "-", "?"),
colClasses = "numeric")
my <- as.matrix(data[1:57600, 2])
mesh <- array(my, dim = c(120, 60, 8))
Ms <- 1350 * 10^3
asd2 = (mesh[70:75, 24:36, 2])/Ms
ort_my <- mean(asd2)
return(ort_my)
}
<environment: 0x00000000151aef20>
我怎样才能做到这一点？
此致
现在我使用 doSNOW 包来做同样的事情
library(foreach)
library(doSNOW)
getDoParWorkers()
getDoParName()
registerDoSNOW(makeCluster(8, type = "SOCK"))
getDoParWorkers()
getDoParName()
strt<-Sys.time()
data1 <- list() # creates a list
filelist <- dir(pattern = "*.omf") # creates the list of all the csv files in the directory
i=1:length(filelist)
readFiles <- function(m){ for (k in 1:length(filelist))
data[[k]] <- read.csv(filelist[k],sep = "",as.is = TRUE, comment.char = "", skip=37); # to read .omf files skip 37 skips 37 line of the header
my <- as.matrix(data[[k]][1:57600,2]);
mesh <- array(my, dim = c(120,60,8));
Ms<-1350*10^3 # A/m
asd2=(mesh[70:75,24:36 ,2])/Ms; # in A/m
ort_my<- mean(asd2);
return(ort_my)
}
out <- foreach(m=1:i, .combine=rbind,.verbose=T) %dopar% readFiles(m)
print(Sys.time()-strt)
我有以下错误消息；
Error in readFiles(m) :
task 1 failed - "object of type 'closure' is not subsettable"
In addition: Warning message:
In 1:i : numerical expression has 70 elements: only the first used
