boost::serialization：是否可以避免模板函数？

我有一个来自外部库的结构，我为其编写了一些非侵入式序列化方法。还有这个结构的包装器，我试图保留从外部结构到这个包装器的所有依赖关系。问题是，所有序列化方法都是模板，因此它们是在头文件中定义的，并将依赖关系从外部库传播到每个序列化包装器的人，这是我试图避免的。这个问题有可能解决吗？

UPD：最初我有这样的事情：

// serialization.h

#include <external_library.h>

template <typename Archive>

void serialize(Archive& archive, ExternalStruct& external_struct, const unsigned int version) {
    // ...
}

然后我尝试使序列化函数成为特定类型存档的非模板：

// serialization.h

#include <boost/archive/binary_iarchive.hpp>
#include <boost/archive/binary_oarchive.hpp>

struct ExternalStruct;

void serialize(boost::archive::binary_iarchive& archive, ExternalStruct& external_struct, const unsigned int version);
void serialize(boost::archive::binary_oarchive& archive, ExternalStruct& external_struct, const unsigned int version);

// serialization.cpp

#include <external_library.h>
#include "serialization.h"

void serialize(boost::archive::binary_iarchive& archive, ExternalStruct& external_struct, const unsigned int version) {
    // ...
}

void serialize(boost::archive::binary_oarchive& archive, ExternalStruct& external_struct, const unsigned int version) {
    // ...
}

但后来我得到了很多编译错误：no type named 'type' in 'struct boost::mpl::greater<boost::serialization::tracking_level<ExternalStruct>, mpl_::int_<0> >' BOOST_STATIC_WARNING(typex::value);

我认为如果您将模板 声明 保留在头文件中，您会得到更好的代码

// serialization.h

#include <external_library.h>

struct ExternalStruct;
template <typename Archive>
void serialize(Archive& archive, ExternalStruct& external_struct, const unsigned int version);

然后，您将模板实现放入隐藏详细信息的源文件中：

// serialization.cpp
#include "serialization.h"

#include <external_library.h>

template <typename Archive>
void serialize(Archive& archive, ExternalStruct& external_struct, const unsigned int version) 
{
    // ... details here
}

最后，您为计划使用的特定存档类型设置“显式实例化”。该代码进入与上面相同的源文件中。

// serialization.cpp continued 
#include <boost/archive/binary_iarchive.hpp>
#include <boost/archive/binary_oarchive.hpp>

template void serialize(boost::archive::binary_iarchive& archive,
     ExternalStruct& external_struct, const unsigned int version); // explicit instantiation.
template void serialize(boost::archive::binary_oarchive& archive,
     ExternalStruct& external_struct, const unsigned int version); // explicit instantiation.