基于逻辑快速 Segue

我想在应用程序首次启动时根据 if 语句快速显示两个视图之一，我该怎么做 这就是逻辑

if signupconfirmed == true {
// have to show one view 
} else {
// have to show another view 
}

一种方法是您可以使用以下代码使用标识符启动 viewController：

var signupconfirmed = true
@IBAction func signUpPressed(sender: AnyObject) {

    if signupconfirmed {
        // have to show one view
        let storyboard = UIStoryboard(name: "Main", bundle: nil)
        let vc = storyboard.instantiateViewControllerWithIdentifier("First") as! SViewController
        self.presentViewController(vc, animated: true, completion: nil)
    } else {
        // have to show another view
        let storyboard = UIStoryboard(name: "Main", bundle: nil)
        let vc = storyboard.instantiateViewControllerWithIdentifier("Second") as! TViewController
        self.presentViewController(vc, animated: true, completion: nil)
    }
}

Update:

您可以在您的AppDelegate.swift

这是你的代码：

func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool {

    let signupconfirmed = NSUserDefaults.standardUserDefaults().boolForKey("SignUp")
    self.window = UIWindow(frame: UIScreen.mainScreen().bounds)
    var initialViewController = UIViewController()
    var storyboard = UIStoryboard(name: "Main", bundle: nil)
    if signupconfirmed {
        initialViewController = storyboard.instantiateViewControllerWithIdentifier("First") as! UIViewController
    } else{
        initialViewController = storyboard.instantiateViewControllerWithIdentifier("Second") as! UIViewController
    }

    self.window?.rootViewController = initialViewController
    self.window?.makeKeyAndVisible()
    return true
}

希望它能帮助你。