IP地址匹配功能

我需要找出ip是否属于ip mask。 例如：

ip = 192.168.0.1 掩码=192.168.0.1/24。

我找到了将 ip 转换为掩码的函数：

inet_cidrtoaddr(int cidr, struct in_addr *addr)
{
        int ocets;

        if (cidr < 0 || cidr > 32) {
                errno = EINVAL;
                return -1;
        }
        ocets = (cidr + 7) / 8;

        addr->s_addr = 0;
        if (ocets > 0) {
                memset(&addr->s_addr, 255, (size_t)ocets - 1);
                memset((unsigned char *)&addr->s_addr + (ocets - 1),
                       (256 - (1 << (32 - cidr) % 8)), 1);
        }

        return 0;
}

如何比较 ip 和 cidr 范围？

因此，将奥利斯的答案放入代码中：

// Check if 192.168.0.1 is inside 192.168.0.0/24
in_addr ip, net, netmask;
inet_aton("192.168.0.1", &ip);
inet_aton("192.168.0.0", &net);

He said:

inet_cidrtoaddr(24, &netmask);
bool is_inside = ((ip.s_addr & netmask.s_addr) == (net.s_addr & netmask.s_addr));

我更喜欢方法虽然：

bool cidr_match(const in_addr &addr, const in_addr &net, uint8_t bits) {
  if (bits == 0) {
    // C99 6.5.7 (3): u32 << 32 is undefined behaviour
    return true;
  }
  return !((addr.s_addr ^ net.s_addr) & htonl(0xFFFFFFFFu << (32 - bits)));
}
bool is_inside = cidr_match(ip, net, 24);

我尝试了一堆不同的输入：https://gist.github.com/duedal/b83303b4988a4afb2a75 https://gist.github.com/duedal/b83303b4988a4afb2a75

如果发现此问题的人也想要 IPv6 解决方案：

bool cidr6_match(const in6_addr &address, const in6_addr &network, uint8_t bits) {
#ifdef LINUX
  const uint32_t *a = address.s6_addr32;
  const uint32_t *n = network.s6_addr32;
#else
  const uint32_t *a = address.__u6_addr.__u6_addr32;
  const uint32_t *n = network.__u6_addr.__u6_addr32;
#endif
  int bits_whole, bits_incomplete;
  bits_whole = bits >> 5;         // number of whole u32
  bits_incomplete = bits & 0x1F;  // number of bits in incomplete u32
  if (bits_whole) {
    if (memcmp(a, n, bits_whole << 2)) {
      return false;
    }
  }
  if (bits_incomplete) {
    uint32_t mask = htonl((0xFFFFFFFFu) << (32 - bits_incomplete));
    if ((a[bits_whole] ^ n[bits_whole]) & mask) {
      return false;
    }
  }
  return true;
}

检查 2001:db8::ff00:42:8329 是否存在于 2001:db8/32 中。请注意 inet_net_pton 非常挑剔，它是 2001:db8/32 而不是 2001:db8::/32。然而 2001:db8::/48 是完全有效的（也称为 2001:db8:0/48）。

in6_addr ip6, net6, net6_48;
memset(&net6, 0, sizeof(net6));
memset(&net6_48, 0, sizeof(net6_48)); 
assert(inet_pton(AF_INET6, "2001:db8::ff00:42:8329", &ip6));

int bits = inet_net_pton(AF_INET6, "2001:db8/32", &net6, sizeof(net6));
assert((bits != -1));  // assert that inet_net_pton understood us
bool is_inside6 = cidr6_match(ip6, net6, bits);

int bits_48 = inet_net_pton(AF_INET6, "2001:db8::/48", &net6_48, sizeof(net6_48));
assert((bits_48 == 48));
bool is_inside6_48 = cidr6_match(ip6, net6_48, bits_48);