Windows 上的 GitLab 运行程序并处理 &%ERRORLEVEL%

在我的 .gitlab-ci.yml 中，我尝试使用 findstr 命令。

findstr /c:"%SOLUTION_DIR%" gitlab.dif > founded.ref

如果 gitlab.dif 中没有匹配“%SOLUTION_DIR%”，此命令会将 %ERRORLEVEL% 设置为 1。

看来 GitLab 运行者将此解释为工作失败。

ERROR: Job failed: exit status 1

有什么解决方法吗？

EDIT :

我的 .gitlab-ci.yml 文件

stages:
  - check
  - build

check_diff:
  stage: check
  script:
    - git diff --name-only origin/develop...HEAD > _gitlab_diff.txt
    - git diff --name-only HEAD~1 >> _gitlab_diff.txt
  artifacts:
    paths:
    - _gitlab_diff.txt
  only:
    refs:
    - merge_requests
    - develop

.generic_build_job:
  stage: build
  dependencies: 
    - check_diff
  before_script:
    - findstr /c:"%SOLUTION_DIR%" "_gitlab_diff.txt" > _check_%SOLUTION_FILE%.txt
    - for /f %%i in ("_check_%SOLUTION_FILE%.txt") do set size=%%~zi
    - if %size% == 0 exit 0
    - cd %SOLUTION_DIR%
  script:
    - '"%NUGET%" restore "%SOLUTION_FILE%"'
    - '"%MSBUILD%" /consoleloggerparameters:ErrorsOnly /maxcpucount /nologo /property:Configuration=Release /verbosity:quiet "%SOLUTION_FILE%"'
  only:
    refs:
    - merge_requests
    - develop

MyApp1:
  variables:
    SOLUTION_DIR: "MyApp1/"
    SOLUTION_FILE: "MyApp1.sln"
  extends: .generic_build_job
  only:
    changes:
      - MyApp1/*

MyApp2:
  variables:
    SOLUTION_DIR: "MyApp2/"
    SOLUTION_FILE: "MyApp2.sln"
  extends: .generic_build_job
  only:
    changes:
      - MyApp2/*

我找到了使用批处理脚本的解决方法。

这是我的skip.bat：

findstr /c:%1 %2 >nul 2>&1
if not %errorlevel% == 0 exit 0