如何在 python 中使用 kNN 动态时间扭曲

2024-01-04

我有一个带有两个标签的时间序列数据集(0 and 1)。我在用动态时间扭曲 (DTW)作为使用 k 最近邻 (kNN) 进行分类的相似性度量,如这两篇精彩的博客文章中所述:

  • https://nbviewer.jupyter.org/github/markdregan/K-Nearest-Neighbors-with-Dynamic-Time-Warping/blob/master/K_Nearest_Neighbor_Dynamic_Time_Warping.ipynb https://nbviewer.jupyter.org/github/markdregan/K-Nearest-Neighbors-with-Dynamic-Time-Warping/blob/master/K_Nearest_Neighbor_Dynamic_Time_Warping.ipynb
  • http://alexminnaar.com/2014/04/16/Time-Series-Classification-and-Clustering-with-Python.html http://alexminnaar.com/2014/04/16/Time-Series-Classification-and-Clustering-with-Python.html

    Arguments
    ---------
    n_neighbors : int, optional (default = 5)
        Number of neighbors to use by default for KNN
    
    max_warping_window : int, optional (default = infinity)
        Maximum warping window allowed by the DTW dynamic
        programming function
    
    subsample_step : int, optional (default = 1)
        Step size for the timeseries array. By setting subsample_step = 2,
        the timeseries length will be reduced by 50% because every second
        item is skipped. Implemented by x[:, ::subsample_step]
    """
    
    def __init__(self, n_neighbors=5, max_warping_window=10000, subsample_step=1):
        self.n_neighbors = n_neighbors
        self.max_warping_window = max_warping_window
        self.subsample_step = subsample_step
    
    def fit(self, x, l):
        """Fit the model using x as training data and l as class labels
    
        Arguments
        ---------
        x : array of shape [n_samples, n_timepoints]
            Training data set for input into KNN classifer
    
        l : array of shape [n_samples]
            Training labels for input into KNN classifier
        """
    
        self.x = x
        self.l = l
    
    def _dtw_distance(self, ts_a, ts_b, d = lambda x,y: abs(x-y)):
        """Returns the DTW similarity distance between two 2-D
        timeseries numpy arrays.
    
        Arguments
        ---------
        ts_a, ts_b : array of shape [n_samples, n_timepoints]
            Two arrays containing n_samples of timeseries data
            whose DTW distance between each sample of A and B
            will be compared
    
        d : DistanceMetric object (default = abs(x-y))
            the distance measure used for A_i - B_j in the
            DTW dynamic programming function
    
        Returns
        -------
        DTW distance between A and B
        """
    
        # Create cost matrix via broadcasting with large int
        ts_a, ts_b = np.array(ts_a), np.array(ts_b)
        M, N = len(ts_a), len(ts_b)
        cost = sys.maxint * np.ones((M, N))
    
        # Initialize the first row and column
        cost[0, 0] = d(ts_a[0], ts_b[0])
        for i in xrange(1, M):
            cost[i, 0] = cost[i-1, 0] + d(ts_a[i], ts_b[0])
    
        for j in xrange(1, N):
            cost[0, j] = cost[0, j-1] + d(ts_a[0], ts_b[j])
    
        # Populate rest of cost matrix within window
        for i in xrange(1, M):
            for j in xrange(max(1, i - self.max_warping_window),
                            min(N, i + self.max_warping_window)):
                choices = cost[i - 1, j - 1], cost[i, j-1], cost[i-1, j]
                cost[i, j] = min(choices) + d(ts_a[i], ts_b[j])
    
        # Return DTW distance given window 
        return cost[-1, -1]
    
    def _dist_matrix(self, x, y):
        """Computes the M x N distance matrix between the training
        dataset and testing dataset (y) using the DTW distance measure
    
        Arguments
        ---------
        x : array of shape [n_samples, n_timepoints]
    
        y : array of shape [n_samples, n_timepoints]
    
        Returns
        -------
        Distance matrix between each item of x and y with
            shape [training_n_samples, testing_n_samples]
        """
    
        # Compute the distance matrix        
        dm_count = 0
    
        # Compute condensed distance matrix (upper triangle) of pairwise dtw distances
        # when x and y are the same array
        if(np.array_equal(x, y)):
            x_s = np.shape(x)
            dm = np.zeros((x_s[0] * (x_s[0] - 1)) // 2, dtype=np.double)
    
            p = ProgressBar(shape(dm)[0])
    
            for i in xrange(0, x_s[0] - 1):
                for j in xrange(i + 1, x_s[0]):
                    dm[dm_count] = self._dtw_distance(x[i, ::self.subsample_step],
                                                      y[j, ::self.subsample_step])
    
                    dm_count += 1
                    p.animate(dm_count)
    
            # Convert to squareform
            dm = squareform(dm)
            return dm
    
        # Compute full distance matrix of dtw distnces between x and y
        else:
            x_s = np.shape(x)
            y_s = np.shape(y)
            dm = np.zeros((x_s[0], y_s[0])) 
            dm_size = x_s[0]*y_s[0]
    
            p = ProgressBar(dm_size)
    
            for i in xrange(0, x_s[0]):
                for j in xrange(0, y_s[0]):
                    dm[i, j] = self._dtw_distance(x[i, ::self.subsample_step],
                                                  y[j, ::self.subsample_step])
                    # Update progress bar
                    dm_count += 1
                    p.animate(dm_count)
    
            return dm
    
    def predict(self, x):
        """Predict the class labels or probability estimates for 
        the provided data
    
        Arguments
        ---------
          x : array of shape [n_samples, n_timepoints]
              Array containing the testing data set to be classified
    
        Returns
        -------
          2 arrays representing:
              (1) the predicted class labels 
              (2) the knn label count probability
        """
    
        dm = self._dist_matrix(x, self.x)
    
        # Identify the k nearest neighbors
        knn_idx = dm.argsort()[:, :self.n_neighbors]
    
        # Identify k nearest labels
        knn_labels = self.l[knn_idx]
    
        # Model Label
        mode_data = mode(knn_labels, axis=1)
        mode_label = mode_data[0]
        mode_proba = mode_data[1]/self.n_neighbors
    
        return mode_label.ravel(), mode_proba.ravel()
    

然而,对于 kNN 分类,这两篇文章使用他们自己的 kNN 算法。

我想使用 sklearn 的选项,例如gridsearchcv在我的分类中。因此,我想知道如何将动态时间规整 (DTW) 与 sklearn kNN 结合使用。

注:我不限于sklearn也很高兴在其他图书馆收到答案

如果需要,我很乐意提供更多详细信息。


您可以对 KNN 使用自定义指标。 因此,您只需要自己实现 DTW(或使用/改编 python 中任何现有的 DTW 实现)[此代码的要点] https://gist.github.com/nikolasrieble/8bd3a83e14c0b2fa66bfa2ddd8828717.

import numpy as np
from scipy.spatial import distance
from sklearn.model_selection import train_test_split
from sklearn.neighbors import KNeighborsClassifier
from sklearn.model_selection import GridSearchCV
from sklearn.metrics import classification_report

#toy dataset 
X = np.random.random((100,10))
y = np.random.randint(0,2, (100))
X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.33, random_state=42)

#custom metric
def DTW(a, b):   
    an = a.size
    bn = b.size
    pointwise_distance = distance.cdist(a.reshape(-1,1),b.reshape(-1,1))
    cumdist = np.matrix(np.ones((an+1,bn+1)) * np.inf)
    cumdist[0,0] = 0

    for ai in range(an):
        for bi in range(bn):
            minimum_cost = np.min([cumdist[ai, bi+1],
                                   cumdist[ai+1, bi],
                                   cumdist[ai, bi]])
            cumdist[ai+1, bi+1] = pointwise_distance[ai,bi] + minimum_cost

    return cumdist[an, bn]

#train
parameters = {'n_neighbors':[2, 4, 8]}
clf = GridSearchCV(KNeighborsClassifier(metric=DTW), parameters, cv=3, verbose=1)
clf.fit(X_train, y_train)



#evaluate
y_pred = clf.predict(X_test)
print(classification_report(y_test, y_pred))

哪个产量

Fitting 3 folds for each of 3 candidates, totalling 9 fits        

[Parallel(n_jobs=1)]: Done   9 out of   9 | elapsed:   29.0s finished

                         precision    recall  f1-score   support

                      0       0.57      0.89      0.70        18
                      1       0.60      0.20      0.30        15

            avg / total       0.58      0.58      0.52        33
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