有没有库函数可以找List1 minus elements that appear in List2
?我一直在谷歌上搜索并没有发现太多。
似乎没有too自己写的很简单。我编写了一个函数来从列表中删除特定元素,但这要简单得多:
let rec difference l arg = match l with
| [] -> []
| x :: xs ->
if (x = arg) then difference xs arg
else x :: difference xs arg;;
这行吗?
let diff l1 l2 = List.filter (fun x -> not (List.mem x l2)) l1
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