PHP 与命令行程序交互

我有一个命令行程序，它从流中获取输入，而不是作为命令行参数。（例如，使用 scanf 获取输入的 C 程序。）我如何使用 PHP 与此应用程序交互？ exec()、shell_exec() 在这里不会有帮助，因为输入不是通过命令行参数。我需要在 PHP 脚本和命令行程序之间建立持续的输入/输出连接，以便用户可以向 PHP 提供输入，PHP 将其转发给程序，然后获取输出，并将其显示给用户。

您可以使用proc_open http://php.net/manual/en/function.proc-open.php为了这。

该页面的示例：

<?php
$descriptorspec = array(
   0 => array("pipe", "r"),  // stdin is a pipe that the child will read from
   1 => array("pipe", "w"),  // stdout is a pipe that the child will write to
   2 => array("file", "/tmp/error-output.txt", "a") // stderr is a file to write to
);

$cwd = '/tmp';
$env = array('some_option' => 'aeiou');

$process = proc_open('php', $descriptorspec, $pipes, $cwd, $env);

if (is_resource($process)) {
    // $pipes now looks like this:
    // 0 => writeable handle connected to child stdin
    // 1 => readable handle connected to child stdout
    // Any error output will be appended to /tmp/error-output.txt

    fwrite($pipes[0], '<?php print_r($_ENV); ?>');
    fclose($pipes[0]);

    echo stream_get_contents($pipes[1]);
    fclose($pipes[1]);

    // It is important that you close any pipes before calling
    // proc_close in order to avoid a deadlock
    $return_value = proc_close($process);

    echo "command returned $return_value\n";
}
?>

Output:

Array
(
    [some_option] => aeiou
    [PWD] => /tmp
    [SHLVL] => 1
    [_] => /usr/local/bin/php
)
command returned 0