rand() 和 srand() 给出了奇怪的相似结果。 rand() 的返回非常相似

这是一个看似常见的问题，所以我希望我听起来不是多余的。但是从 rand() 返回的范围应该在 0 和 RAND_MAX 之间，但是，当我执行一个非常简单的 rand 语句时，我总是得到一个非常小的范围内的返回值。

该范围类似于 1,4XX,XXX,XXX。我认为这可能是一个时钟问题，所以我等了三十分钟，但仍然得到相同范围内的数字。

以下是二十分钟前的一些示例输出：

Matthews-Macbook-Pro:Data_Structures matthewwright$ ./main
1439810968
80
Matthews-Macbook-Pro:Data_Structures matthewwright$ ./main
1439827775
29
Matthews-Macbook-Pro:Data_Structures matthewwright$ ./main
1439827775
29
Matthews-Macbook-Pro:Data_Structures matthewwright$ ./main
1439844582
78
Matthews-Macbook-Pro:Data_Structures matthewwright$ ./main
1439878196
29
Matthews-Macbook-Pro:Data_Structures matthewwright$ ./main
1439895003
78

这是刚才的输出示例：

Matthews-Macbook-Pro:Data_Structures matthewwright$ ./main
1456483512
78
Matthews-Macbook-Pro:Data_Structures matthewwright$ ./main
1456500319
80
Matthews-Macbook-Pro:Data_Structures matthewwright$ ./main
1456500319
80
Matthews-Macbook-Pro:Data_Structures matthewwright$ ./main
1456517126
29
Matthews-Macbook-Pro:Data_Structures matthewwright$ ./main
1456533933
78

我知道 rand() 并不完美，但这看起来太相似而不是正确的。如果范围是 0 - RAND_MAX，则返回的每个数字都在同一范围内似乎很奇怪。

这是我正在测试的代码：

#include <iostream>
#include <stdio.h>      /* printf, scanf, puts, NULL */
#include <stdlib.h>     /* srand, rand */
#include <time.h>       /* time */

int main(int argc, char const *argv[])
{
    /* declarations */
    srand(time(NULL));

    std::cout << std::rand() << std::endl;
    std::cout << std::rand()%100 << std::endl;
    return 0;
}

我认为我不需要所有这些 #include 语句，但我看到其他人使用它们，所以我将它们包含在内，以防它会影响我的输出，但事实并非如此。

Edit

所以@Mgetz 和@Curious 提供的链接非常有帮助。以巩固，

信息页面：http://en.cppreference.com/w/cpp/numeric/random/uniform_int_distribution http://en.cppreference.com/w/cpp/numeric/random/uniform_int_distribution

超级有用的讲座（真正的，观看这个）：https://channel9.msdn.com/Events/GoingNative/2013/rand-Considered-Harmful https://channel9.msdn.com/Events/GoingNative/2013/rand-Considered-Harmful

我把我在讲座中听到的内容总结在自己的笔记上，这样如果我忘记了，就不用再重新研究了。我没有在这里编写代码，大部分代码都在上面链接的“信息页面”中。大多数评论包含讲座中的信息，尽管不是讲座中的逐字内容。再次，我真的建议观看。它内容丰富，信息丰富。

#include <iostream>
#include <random>

int main(int argc, char const *argv[])
{
    /* https://channel9.msdn.com/Events/GoingNative/2013/rand-Considered-Harmful */

    /* Randomness Verson 1 : Deterministic */
    std::mt19937 mt(1234);
    std::uniform_int_distribution<int> dist(0,127);
    /* Default is int, but we could specify others.
     * The range is [inclusive, inclusive]
     * 
     * Above is Mersenne Twister RNG. It is deterministic, meaning we can get the same result
     * if we use "std::mt19937 mt(1234)"; or something like that. This could be useful for some
     * people (He mentions games, some experiments, et cetera). It is stupid fast.
     * 
     * However, it isn't cryptographically secure, but it pretty random as random goes. If you
     * track the output though, you could guess the next numbers, so don't use it for anything
     * secure.
     */

    /* Randomness Verson 2 */
    std::random_device rd;  //Will be used to obtain a seed for the random number engine
    std::mt19937 gen(rd()); //Standard mersenne_twister_engine seeded with rd()
    std::uniform_int_distribution<int> dis(0, 127); // Inclusive
    /* This is not reproducible. This is not deterministic.
     * "Possibly Crypto-secure." Seems like using Random Device makes this near perfect random,
     * assuming some conditions. I'm not a man who's written security software, and if you are 
     * writing security software, I assume you're not looking at StackOverflow to figure out how
     * to do random numbers. The way he talked about it in the lecture made this seem much more 
     * secure, but I'm not sure what I'm talking about when it comes to these things
     */

    for (int i = 0; i < 3; ++i)
    {
        /* Below would output the pure Mersenne Twister output, deterministic. This seems to
         * be pretty random, but it isn't totally random. */
        std::cout << dist(mt) << " ";

        /* And below would output the random device output. This should be slower, but
         * more truly random. */

        //Use dis to transform the random unsigned int generated by gen into an int in [1, 6]
        std::cout << dis(gen) << " ";

        std::cout<< std::endl;
    }
}

使用模运算符会给生成的“随机数”带来一定程度的偏差。进一步做好工作rand()函数是实现定义的，不遵循跨平台的标准算法。

考虑使用更现代的 C++11 随机数生成功能，这些功能使用标准的广泛接受的随机数生成算法，跨平台工作相同（当然给定相同的种子）。

请参阅以下示例std::uniform_int_distribution 的 cppreference 页面 http://en.cppreference.com/w/cpp/numeric/random/uniform_int_distribution

#include <random>
#include <iostream>

int main()
{
    std::random_device rd;  //Will be used to obtain a seed for the random number engine
    std::mt19937 gen(rd()); //Standard mersenne_twister_engine seeded with rd()
    std::uniform_int_distribution<> dis(1, 6);

    for (int n=0; n<10; ++n)
        //Use dis to transform the random unsigned int generated by gen into an int in [1, 6]
        std::cout << dis(gen) << ' ';
    std::cout << '\n';
}

这是 Stephan Levavej 的精彩演讲的链接，该演讲更深入地探讨了这一点https://channel9.msdn.com/Events/GoingNative/2013/rand-Considered-Harmful https://channel9.msdn.com/Events/GoingNative/2013/rand-Considered-Harmful