我有以下元素:
a = Row(ts=1465326926253, myid=u'1234567', mytype=u'good')
Row是Spark数据框架的Row类。我想追加一个新字段a
, 以便a
看起来像:
a = Row(ts=1465326926253, myid=u'1234567', mytype=u'good', name = u'john')
这是一个有效的更新答案。首先,您必须创建一个字典,然后更新该字典,然后将其写入 pyspark Row。
代码如下:
from pyspark.sql import Row
#Creating the pysql row
row = Row(field1=12345, field2=0.0123, field3=u'Last Field')
#Convert to python dict
temp = row.asDict()
#Do whatever you want to the dict. Like adding a new field or etc.
temp["field4"] = "it worked!"
# Save or output the row to a pyspark rdd
output = Row(**temp)
#How it looks
output
In [1]:
Row(field1=12345, field2=0.0123, field3=u'Last Field', field4='it worked!')
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