这是我的代码段:
set CMS_SQL="cms91_to_913.json cms913_to_9132.json cms9132_to_9133.json cms9133_to_10100.json"
set CMS_FROM_VERSION="cms913_"
set CMS_TO_VERSION="to_9133.json"
Both CMS_FROM_VERSION and CMS_TO_VERSION是变量
我想提取子字符串"cms913_to_9132.json cms9132_to_9133.json"
from %CMS_SQL%
只是想获取之间的子字符串%CMS_FROM_VERSION% and %CMS_TO_VERSION%
包含这两个变量值
不想使用文件来执行此操作,也不想对数字进行硬编码来获取子字符串,因为这两个字符串是变量。
如何提取这两个字符串之间的子字符串?
谢谢
重申一下我的评论,以下内容不知道或计算子字符串的长度,它只是从字符串中删除前两个和最后两个字符:
Set "String=AB134SSPQS"
Set "subString=%String:~2,-2%"
Echo %subString%
If AB
and QS
在所需子字符串之前和之后,但不一定开始和开始字符串,那么也许这对您有用:
Rem Looking for a file.txt substring preceded by AB and succeeded by QS
@Echo Off
For /F "Delims=" %%A In ('FindStr /I "AB.*QS" "file.txt"') Do Call :Sub "%%A"
Pause
GoTo :EOF
:Sub
Set "Line=%~1"
Set "Up2Sub=%Line:*AB=%"
Set "SubStr=%Up2Sub:QS="&:"%"
Echo %SubStr%
Exit /B
我不得不编造一个场景(see Rem
),因为您没有提供足够的信息作为答案的基础。
Edit
Set "String=AB134SSPQS"
Set "Up2Sub=%String:*AB=%"
Set "SubStr=%Up2Sub:QS="&:"%"
Echo %SubStr%
Edit2
正如您的其他问题中给出的,并根据您现在更改的问题在此处添加,这是一种方法:
@Echo Off
Set "CMS_SQL=cms91_to_913.json cms913_to_9132.json cms9132_to_9133.json cms9133_to_10100.json"
Set "CMS_FROM_VERSION=cms913_"
Set "CMS_TO_VERSION=to_9133.json"
For /F "Delims=" %%A In ('Echo %%CMS_SQL:*%CMS_FROM_VERSION%^=%%'
) Do Set "SUBSTRING=%CMS_FROM_VERSION%%%A"
For /F "Delims=" %%A In ('Echo %%SUBSTRING:%CMS_TO_VERSION%^=^&:%%'
) Do Set "SUBSTRING=%%A%CMS_TO_VERSION%"
Set SUBSTRING
Pause
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