在Python中将秒转换为周-天-小时-分钟-秒

我正在尝试编写一个“输入秒数”的 Python 脚本，并在周、天、小时、分钟和秒内获得结果。这是我所拥有的，但我没有得到正确的答案。我究竟做错了什么？

seconds = raw_input("Enter the number of seconds:")
seconds = int(seconds)

minutes = seconds/60

seconds = seconds % 60

hours = minutes/60
hours = seconds/3600

minutes = minutes % 60

days = hours/24
days = minutes/1440
days = seconds/86400

hours = hours % 60
hours = minutes % 60
hours = seconds % 3600

weeks = days/7
weeks = hours/168
weeks = minutes/10080
weeks = seconds/604800

days = days % 1
days = hours % 24
days = minutes % 1440
days = seconds % 86400

weeks = weeks % 1
weeks = days % 7
weeks = hours % 168
weeks = minutes % 10080
weeks = seconds % 604800

print weeks, 'weeks', days, 'days', hours, 'hours', minutes, 'minutes', seconds, 'seconds'

仅从基本转换原理来看：

weeks = seconds / (7*24*60*60)
days = seconds / (24*60*60) - 7*weeks
hours = seconds / (60*60) - 7*24*weeks - 24*days
minutes = seconds / 60 - 7*24*60*weeks - 24*60*days - 60*hours
seconds = seconds - 7*24*60*60*weeks - 24*60*60*days - 60*60*hours - 60*minutes

做同样事情的一种不太吵闹的方式：

weeks = seconds / (7*24*60*60)
seconds -= weeks*7*24*60*60
days = seconds / (24*60*60)
seconds -= days*24*60*60
hours = seconds / (60*60)
seconds -= hours*60*60
minutes = seconds / 60
seconds -= minutes *60

再次相同的事情的更干净的版本divmod返回元组中除法结果和余数的函数(division, remainder):

weeks, seconds = divmod(seconds, 7*24*60*60)
days, seconds = divmod(seconds, 24*60*60)
hours, seconds = divmod(seconds, 60*60)
minutes, seconds = divmod(seconds, 60)

基本上，这个解决方案最接近您的尝试，因为这就是divmod does:

weeks, seconds = divmod(seconds, 7*24*60*60)

相当于

weeks = seconds / (7*24*60*60)
seconds = seconds % (7*24*60*60)

在这里，我们本质上是找到我们时间中的整周数，并保留删除这些周后剩下的内容。

你也可以从另一端让它变得更漂亮：

minutes, seconds = divmod(seconds, 60)
hours, minutes = divmod(minutes, 60)
days, hours = divmod(hours, 24)
weeks, days = divmod(days, 7)

这背后的想法是，你的答案中的秒数是除以分钟后的余数；分钟是将所有分钟除以小时等的余数...这个版本更好，因为您可以轻松地将其调整为月，年等...