Android 在 HttpClient 中收到 403 后得到响应

我有这样的代码：

HttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(server);

try {
    JSONObject params = new JSONObject();
    params.put("email", email);

    StringEntity entity = new StringEntity(params.toString(), "UTF-8");
    httpPost.setHeader("Content-Type", "application/json;charset=UTF-8");
    httpPost.setEntity(entity);

    ResponseHandler<String> responseHandler = new BasicResponseHandler();
    String responseBody = httpClient.execute(httpPost, responseHandler);
    JSONObject response = new JSONObject(responseBody);
        fetchUserData(response);

    saveUserInfo();

    return true;
} catch (ClientProtocolException e) {
    Log.d("Client protocol exception", e.toString());
    return false;
} catch (IOException e) {
    Log.d`enter code here`("IOEXception", e.toString());
    return false;
} catch (JSONException e) {
    Log.d("JSON exception", e.toString());
    return false;
}

即使我有 HTTP 403 Forbidden 来获取错误消息，我也希望得到响应

The BasicResponseHandler仅当返回成功代码 (2xx) 时才返回您的数据。但是，您可以非常轻松地编写自己的ResponseHandler始终将响应正文返回为String, e.g.

    ResponseHandler<String> responseHandler = new ResponseHandler<String>() {
    @Override
    public String handleResponse(HttpResponse response) throws ClientProtocolException, IOException {
        return EntityUtils.toString(response.getEntity());
    }
    };

或者，您可以使用其他重载执行方法 http://developer.android.com/reference/org/apache/http/client/HttpClient.html#execute%28org.apache.http.client.methods.HttpUriRequest%29 on HttpClient这不需要ResponseHandler并返回给您HttpResponse直接地。然后打电话EntityUtils.toString(response.getEntity())以同样的方式。

要获取响应的状态代码，您可以使用HttpResponse.getStatusLine().getStatusCode()并与其中的静态整数之一进行比较HttpStatus班级。例如。代码“403”是HttpStatus.SC_FORBIDDEN。您可以根据返回的状态代码采取与您的应用程序相关的特定操作。