主题分布：在python中进行LDA后如何查看哪个文档属于哪个主题

我能够运行 gensim 中的 LDA 代码，并获得前 10 个主题及其各自的关键字。

现在，我想进一步了解 LDA 算法的准确性，方法是查看它们将哪些文档聚类到每个主题中。这在 gensim LDA 中可能吗？

基本上我想做这样的事情，但是在 python 中并使用 gensim。

LDA with topicmodels，如何查看不同文档属于哪些主题？ https://stackoverflow.com/questions/14875493/lda-with-topicmodels-how-can-i-see-which-topics-different-documents-belong-to

使用主题的概率，您可以尝试设置一些阈值并将其用作聚类基线，但我确信有比这种“hacky”方法更好的聚类方法。

from gensim import corpora, models, similarities
from itertools import chain

""" DEMO """
documents = ["Human machine interface for lab abc computer applications",
             "A survey of user opinion of computer system response time",
             "The EPS user interface management system",
             "System and human system engineering testing of EPS",
             "Relation of user perceived response time to error measurement",
             "The generation of random binary unordered trees",
             "The intersection graph of paths in trees",
             "Graph minors IV Widths of trees and well quasi ordering",
             "Graph minors A survey"]

# remove common words and tokenize
stoplist = set('for a of the and to in'.split())
texts = [[word for word in document.lower().split() if word not in stoplist]
         for document in documents]

# remove words that appear only once
all_tokens = sum(texts, [])
tokens_once = set(word for word in set(all_tokens) if all_tokens.count(word) == 1)
texts = [[word for word in text if word not in tokens_once] for text in texts]

# Create Dictionary.
id2word = corpora.Dictionary(texts)
# Creates the Bag of Word corpus.
mm = [id2word.doc2bow(text) for text in texts]

# Trains the LDA models.
lda = models.ldamodel.LdaModel(corpus=mm, id2word=id2word, num_topics=3, \
                               update_every=1, chunksize=10000, passes=1)

# Prints the topics.
for top in lda.print_topics():
  print top
print

# Assigns the topics to the documents in corpus
lda_corpus = lda[mm]

# Find the threshold, let's set the threshold to be 1/#clusters,
# To prove that the threshold is sane, we average the sum of all probabilities:
scores = list(chain(*[[score for topic_id,score in topic] \
                      for topic in [doc for doc in lda_corpus]]))
threshold = sum(scores)/len(scores)
print threshold
print

cluster1 = [j for i,j in zip(lda_corpus,documents) if i[0][1] > threshold]
cluster2 = [j for i,j in zip(lda_corpus,documents) if i[1][1] > threshold]
cluster3 = [j for i,j in zip(lda_corpus,documents) if i[2][1] > threshold]

print cluster1
print cluster2
print cluster3

[out]:

0.131*trees + 0.121*graph + 0.119*system + 0.115*user + 0.098*survey + 0.082*interface + 0.080*eps + 0.064*minors + 0.056*response + 0.056*computer
0.171*time + 0.171*user + 0.170*response + 0.082*survey + 0.080*computer + 0.079*system + 0.050*trees + 0.042*graph + 0.040*minors + 0.040*human
0.155*system + 0.150*human + 0.110*graph + 0.107*minors + 0.094*trees + 0.090*eps + 0.088*computer + 0.087*interface + 0.040*survey + 0.028*user

0.333333333333

['The EPS user interface management system', 'The generation of random binary unordered trees', 'The intersection graph of paths in trees', 'Graph minors A survey']
['A survey of user opinion of computer system response time', 'Relation of user perceived response time to error measurement']
['Human machine interface for lab abc computer applications', 'System and human system engineering testing of EPS', 'Graph minors IV Widths of trees and well quasi ordering']

只是为了更清楚地说：

# Find the threshold, let's set the threshold to be 1/#clusters,
# To prove that the threshold is sane, we average the sum of all probabilities:
scores = []
for doc in lda_corpus
    for topic in doc:
        for topic_id, score in topic:
            scores.append(score)
threshold = sum(scores)/len(scores)

上面的代码是所有文档的所有单词和所有主题的分数总和。 然后通过分数的数量对总和进行归一化。