将 Json String 反序列化为多种 Object 类型

我有一个从网络服务获得的 Json 字符串；它有一个集合列表，每个集合代表一个对象，例如：

  [ // Root List
    [ // First Collection : Team Object
      {
        "id": 1,
        "team_name": "Equipe Saidi",
        "is_active": true,
        "last_localisation_date": "2015-05-06T13:33:15+02:00"
      },
      {
        "id": 3,
        "team_name": "Equipe Kamal",
        "is_active": true,
        "last_localisation_date": "2015-05-06T09:22:15+02:00"
      }
     ],
     [// Second Collection : user Object
      {
        "id": 1,
        "login": "khalil",
        "mobile_password": "####",
        "first_name": "Abdelali",
        "last_name": "KHALIL",
        "email": "[email protected] /cdn-cgi/l/email-protection",
        "role": "DR",
        "is_active": true,
        "charge": false
      },
      {
        "id": 2,
        "login": "ilhami",
        "mobile_password": "####",
        "first_name": "Abdellah",
        "last_name": "ILHAMI",
        "email": "[email protected] /cdn-cgi/l/email-protection",
        "role": "DR",
        "is_active": true,
        "charge": false
      }
    ]
  ]

我的实际代码（当然不起作用）：

 public async Task TeamsAndMobileUsers()
    {
        string data = "";
        IList<User> MobileUsersList = new List<User>();
        IList<Team>  TeamsList  = new List<Team>();
        try
        {
            data = await GetResponse(PATH + TEAMS_USERS_URL);
            TeamsList = JsonConvert.DeserializeObject<List<Team>>(data);   
           MobileUsersList = JsonConvert.DeserializeObject<List<User>>(data); 

            // Inserting
            await SetAchievedActions(TeamsList);

        }
        catch (Exception e) { 
            _errors.Add(e.Message); 
        }
    }

我使用 Json.net 和 C#。我找不到解决方案，我读过应该使用 JsonReader 并将其 SupportMultipleContent 属性设置为 true 但我不知道如何实现该解决方案。

正如@YeldarKurmangaliyev 已经说过的，你的 json 有两个不同的对象，我认为你可以这样做：

var j = JArray.Parse(data);
TeamsList = JsonConvert.DeserializeObject<List<Team>>(j[1].ToString());
MobileUsersList = JsonConvert.DeserializeObject<List<User>>(j[2].ToString());